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sineoko [7]
2 years ago
8

Unit 8 Multiple Choice Questions

Chemistry
1 answer:
max2010maxim [7]2 years ago
8 0

Answer:

C

Explanation:

just did it

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What equation do you use to go from mass to mole?
liq [111]

Answer:

Number of moles = mass/molar mass

Explanation:

Given data:

mass of Al = 11 g

Moles = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of aluminium is 27 g/mol

Now we will put the values in formula.

Number of moles = 11 g/ 27 g/mol

Number of moles = 0.41

The number of moles in 11 g Al are 0.41 mol.

5 0
3 years ago
When heated, KCIO3 decomposes into KCl and O2
Oksana_A [137]

Answer:

Explanation:

First, the KClO3 moles is determined by using given grams of KCl produced from the reaction.

Next, the moles of O2 produced is obtained by using the moles of KClO3 which then, finally converted into mass of O2.

Analyzing the given chemical reaction clearly shows that, 2 moles of KClO3 produces 2 moles of KCl and 3 moles of O2.

From the given grams of KCl produced the initial grams of KClO3 used in the reaction is determined as follows,

5 0
3 years ago
10. Given the reaction below, which is the reduced substance? Mg + Cl2 Mg2+ + 2Cl-
atroni [7]

Answer:

2Cl-

Explanation:

When a substance is reduced, it gains electrons. Because electrons are negatively charged, the substance that is reduced will have a negative charge. 2Cl- is the substance that was reduced because it became negative.

7 0
3 years ago
What makes electrons jumo to other orbits around the nucleus then fall again?
Tamiku [17]

Answer:

The higher the excitation state, the more energy the electron contains. When an electron absorbs energy, it jumps to a higher orbital. ... An electron in an excited state can release energy and 'fall' to a lower state.

7 0
3 years ago
Read 2 more answers
How much work is needed to assemble an atomic nucleus containing three protons (such as Be) if we model it as an equilateral tri
klio [65]

Answer:

2.16 MeV

Explanation:

To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;

U = \frac{3}{4 \pi E_o} (\frac{e^2}{r})

where:

\frac{1}{4 \pi E_o} = proportionality constant = (9*10^9N.m^2/C^2)

e = magnitude of the charge of each electron = (1.6*10^{-19} C)^2

r = length of each side of the vertex = (2.00*10^{-15}m)

So; replacing our values into above equation; we have:

U = 3\frac{(9*10^9N.m^2/C^2)(1.6*10^{-19} C)^2}{(2.00*10^{-15}m)}

U = 3.456 × 10 ⁻¹³ J

If we have to convert our unit from J to Mev; then we are going to have:

U = 3.456 × 10 ⁻¹³ J (\frac{1 MeV}{1.602*10^{-13}J})

U = 2.16 MeV

Therefore, the amount of work done needed to assemble an atomic nucleus =  2.16 MeV

8 0
3 years ago
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