(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
a(6) = 37.97
Step-by-step explanation:
If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is
a(n) = 5*r^(n - 1).
Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97
Answer:
honestly math is my worst subject but i think its 2 im really srry i think thats wrong tho
Step-by-step explanation:
The answer is D !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
n = m-a
Step-by-step explanation:
The formula is : ...(1)
a is actual cost of an item
m is original price
n is amount of coupon
We need to solve the formula for the amount of coupen.
Subtracting m to the both sides of equation (1).
a-m = m-n-m
-n=a-m
or
n = m-a
So, the formula for the amount of coupon is n = m-a.
