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3 years ago

Solve the expression x^2-100=0

Mathematics

1 answer:

enot [183]3 years ago

6 0

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± $\sqrt{100}$ ← note plus or minus, hence

x = ± 10

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(8,10) (-7,14) find the slope of the line through each pair of points.

DochEvi [55]

Slope is rise over run which is -4/15

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3 years ago

Read 2 more answers

2x(squared) + 23x-19=0

Helen [10]

Use quadratic formula

for ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x= $\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x= $\frac{-23+/- \sqrt{529-152} }{4}$
x= $\frac{-23+/- \sqrt{377} }{4}$

x= $\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$

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3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$