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Nataly [62]
3 years ago
14

Solve the expression x^2-100=0

Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± \sqrt{100} ← note plus or minus, hence

x = ± 10

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9 and 5 twelves, minus 6 and 7 twelves
mash [69]

Answer:

2 5/6

Step-by-step explanation:

9 5/12 - 6 7/12

We will need to borrow from the 9

8 12/12 + 5/12 - 6  7/12

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5 0
3 years ago
Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21
yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to -4x+7y=21.

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

-4x+7y=21

Slope of this line is

m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{-4}{7}

m_1=\dfrac{4}{7}

Product of slope of two perpendicular lines is -1.

m_1\times m_2=-1

\dfrac{4}{7}\times m_2=-1

m_2=-\dfrac{7}{4}

Now, slope of required line is -\dfrac{7}{4} and it passes through (1,-2). So, the equation of line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-2)=-\dfrac{7}{4}(x-1)

4(y+2)=-7(x-1)

4y+8=-7x+7

4y+7x=7-8

7x+4y=-1

Therefore, the equation of required line is 7x+4y=-1.

7 0
3 years ago
Need help with this problem, it's got me stuck PLZ
faust18 [17]

24x^2 +25x - 47                     53

----------------------- = -8x -3 - ---------------

ax-2                                     ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53                    

-----------------------         = -8x -3

ax-2                                    

24x^2 +25x +6                  

-----------------------         = -8x -3

ax-2      

multiply each side by ax-2

24x^2 +25x +6   = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6  = -8ax^2 +16x-3ax +6

24 = -8a      25 = 16 -3a

a = -3          9 = -3a

                   a = -3


Choice B

6 0
3 years ago
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