All categories

3 years ago

Solve the expression x^2-100=0

Mathematics

1 answer:

enot [183]3 years ago

6 0

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± $\sqrt{100}$ ← note plus or minus, hence

x = ± 10

You might be interested in

What is the value of x to the nearest tenth?<br> 3.1<br> 4.8<br> 5.4<br> 3.5

Tanya [424]

Answer:

5.4

Step-by-step explanation:

I am not really sure about this type of problem, but a diameter has to cross the midpoint of the circle the dark dot and hit two point on both side of the circle. Yet the line 9.6 is not a diameter since it didn't go through the center, so the diameter has to be longer than 9.6. But x is looking for radius. so divide 9.6 by 2 u get 4.8 but that is not a diameter and the real diameter is longer that mean the radius is longer so the only answer is 5.4

8 0

4 years ago

I made my own tricky math question. But I don't know if its tricky for you. Amelia has 1 notebook on her desk, she put her noteb

fomenos

Answer:

1 thing, her pouch

Step-by-step explanation:

you sayed that she took her notebook away and the only thing onher desk is her pouch

5 0

3 years ago

A chef makes a fruit salad using pears and mangos. Pears and mangos each cost $2.25 per fruit. The chef buys x pears and y mango

GrogVix [38]

Answer:

P=2.25x-----------1

M=2.25y----------2

Step-by-step explanation:

Step one:

given data

we are told that the cost of pears= $2.25 each

and cost of mango= $2.25 each

Step two:

the chef bought x pears and y mangoes

let the total cost of pears be P

and for mango be M

P=2.25x-----------1

M=2.25y----------2

3 0

3 years ago

Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.

dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship: