Question

Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope form is y + 1 = (x – 8).

Answer 1

Answer: The answer is 2x + -3y =19

hope this helps (:

Answer 2

Answer:

$2x-3y=19$

Step-by-step explanation:

we have the ordered pairs

(8, –1) and (2, –5)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values in the formula

$m=\frac{-5+1}{2-8}$

$m=\frac{-4}{-6}$

simplify

$m=\frac{2}{3}$

The equation of the line in point slope form is

$y-y1=m(x-x1)$

we have

$m=\frac{2}{3}$

$point\ (8,-1)$

substitute

$y+1=\frac{2}{3}(x-8)$

Convert to standard form

The equation of the line in standard form is equal

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y+1=\frac{2}{3}(x-8)$

Multiply by 3 both sides to remove the fraction

$3y+3=2(x-8)$

apply distributive property right side

$3y+3=2x-16$

Group the variables in one side and the constants in the other side

$2x-3y=3+16$

$2x-3y=19$ ---> equation in standard form