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3 years ago

Ax-bx+y=z the formula that could be used to find x

Mathematics

2 answers:

Illusion [34]3 years ago

5 0

ax-bx+y=z the formula that could be used to find x

Answer:

Art [367]3 years ago

4 0

Answer:

x = $\frac{z-y}{a-b}$

Step-by-step explanation:

Given

ax - bx + y = z ( subtract y from both sides )

ax - bx = z - y ( factor out x on the left side )

x(a - b) = z - y ( divide both sides by (a - b) )

x = $\frac{z-y}{a-b}$

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Get a number 100 by using four sevens (7’s) and a one (1)?

Oksanka [162]

Answer 1: 177 – 77 = 100

Answer 2: (7+7) * (7 + (1/7)) = 100

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2 years ago

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I need help Whats the Domain and range

lukranit [14]

Domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

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3 years ago

Please help! Which angle is a vertical angle with ZEFD? - - - -

mixer [17]

Answer:

<AFB

Step-by-step explanation:

The angle that is a vertical angle with <EFD would be the angle that is vertically opposite and equal to <EFD.

Taking a look at the diagram, yiu would observe that <AFB is vertically opposite to <EFD. Therefore, <AFB is a vertical angle with <EFD.

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3 years ago

. A. 139 B. 147° C. 155 D. 157 PLEASE HELP ASAAAPP!

enyata [817]

Answer:

$\huge\boxed{157 \ \ \text{degrees}}$

Step-by-step explanation:

In order to find the value of ∠EFB here, we have to note our angle relationships.

We know that ∠CFE is already 90°. We also know that ∠CFA is 90°. Angle ∠AFB is inside ∠CFA. Since we know the measure of ∠AFB, we can find the measure of ∠BFC.

$23 + x = 90\\\\x = 90-23\\\\x = 67$

Now that we know ∠CFE and ∠BFC, which together make ∠BFE, we can add these angles up.

$90+67=157$

Hope this helped!

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3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

2 years ago