Question

A car moving at 10.0 m/s encounters a bump that has a circular cross-section with a radius of 30.0 m. What is the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?
A) 200 N
B) 389 N
C) 789 N
D) 589 N

Answer 1

Answer:

option B

Explanation:

given.

car is moving at = 10 m/s

bump of radius = 30 m

normal force = ?

mass of the passenger = 60 kg

m × g = 60 × 9.81 N

normal force acting

                 =$mg - \dfrac{mv^2}{R}$

                 =$60\times 9.81 - \dfrac{60\times 10^2}{30}$

                 =388.6 N

the normal force acting is equal to 389 N

hence, the correct answer is option B

Answer 2

Answer:

force at the top will be 388 N which is nearly equal to 389

option (b) is correct

Explanation:

We have given velocity of the moving car v = 10 m/sec

Radius of the circular section r = 30 m

Mass of the passenger m = 60 kg

Acceleration due to gravity $g=9.8m/sec^2$

At the top normal force is given by $noraml\ force=mg-\frac{mv^2}{r}$

So force at top will be $F=60\times 9.8-\frac{60\times 10^2}{30}=388N$

So force at the top will be 388 N which is nearly equal to 389

So option (b) is correct