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LenaWriter [7]
4 years ago
15

A 6.0-g bullet leaves the muzzle of a rifle with a speed of 336 m/s. what force (assumed constant) is exerted on the bullet whil

e it is traveling down the 0.83-m-long barrel of the rifle?
Physics
1 answer:
nikklg [1K]4 years ago
4 0
The work done on the bullet is force•distance. This is also equivalent to the energy it has leaving the muzzle (work energy theorem). This kinetic energy is (1/2)(0.006kg)(336m/s)^2=338.7J. Then 338.7J=F•0.83m
F=338.7/0.83=408N
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Answer:

Magnitude of kinetic force is the product of the normal force and the coefficient of kinetic friction.

Explanation:

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Suppose a certain battery has an internal emf of 9.00 V but the potential difference across its terminals is only 80.0 % of that
Rudiy27

Answer:

1140.48\times 10^{-6}J

Explanation:

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Answer:

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a )

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