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3 years ago

A ball is dropped out of a window and falls for 8.75 s. What is the ball's final velocity?

Physics

1 answer:

Kipish [7]3 years ago

3 0

Answer:

Final velocity of ball is 85.75 m/s

Explanation:

According to the problem, ball is dropped from the window and it experience an acceleration due to Earth's gravity which is denoted by g.

Initially, the ball is at rest, so its initial velocity is zero. The ball takes 8.75 s to fall from the window and hits the ground.

The equation of motion for constant acceleration is :

v = u + at

Here v is final velocity, u is initial velocity, t is time and a is acceleration.

In this case, u is zero and a is equal to g. So, the equation becomes :

v = gt

Substitute 8.75 s for t and 9.8 m/s² for g in the above equation.

v = 9.8 x 8.75

v = 85.75 m/s

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3 years ago

Suppose the ring rotates once every 4.30 ss . If a rider's mass is 58.0 kgkg , with how much force does the ring push on her at

Stells [14]

Answer:

422.36 N

Explanation:

given,

time of rotation = 4.30 s

T = 4.30 s

Assuming the diameter of the ring equal to 16 m

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$v = \dfrac{2\pi R}{T}$

$v = \dfrac{2\pi\times 8}{4.30}$

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now, Force does the ring push on her at the top

$- N - m g = \dfrac{-mv^2}{R}$

$N + m g = \dfrac{mv^2}{R}$

$N = \dfrac{mv^2}{R}- m g$

$N = m(\dfrac{v^2}{R}- g)$

$N = 58\times (\dfrac{11.69^2}{8}- 9.8)$

N = 422.36 N

The force exerted by the ring to push her is equal to 422.36 N.

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3 years ago

A ___ is the unit of measurement for force.

bogdanovich [222]

Answer:

Newton (N)

Explanation:

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3 years ago

How much energy to be removed to drop the temperature of 5.7kg of wood from 20degrees to 7degrees. #100points

Neporo4naja [7]

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3 years ago

Read 2 more answers

A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high te

Nataly [62]

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

$\Delta L=\alpha L_{0}\Delta T$

Where:

L(0) is the initial length
ΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))
ΔL is the final length minus the initial length (L(f)-L(0))
α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)

So, we have:

$L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})$

$L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})$

$L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)$

$L_{f}=0.117\: m$

Therefore, the length at the final temperature is 11.7 cm.

I hope it helps you!

7 0

3 years ago