Given parameters:
Duration of crash = 9min
Velocity before crash = 2000 yards per second
Unknown:
Acceleration of the plane = ?
Solution:
Acceleration is the change of velocity with time.
Acceleration = 
where v is the final velocity
u is the initial velocity
t is the time taken
We need to convert the time into seconds from min;
60s = 1 min
So, 9min = 60 x 9 = 540s
So input the parameters and solve;
Acceleration = 
= 3.7yards/s²
The acceleration of the plane is 3.7yards/s²
Area=54
l2=54
l =3√6
volume=(3√6)3
=396.81
Answer:
If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.
Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:
PE = qV
where q =1.6 x 10^-19 C
and V = 1.00 V
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:
PE* = 0,
KE* = 1/(2mv^2)
Now since
PE + KE = Total energy =PE* + KE*
Therefore,
qV + 0 = 0 + 1/2mv^2
Or
KE = qV = 1.6 10^-19 J
100N to the left. Newton's 3rd law action and reaction
Answer:
He could re read his answear.
Explanation:
