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Alja [10]
3 years ago
14

How can I select tools and techniques to analyze the relationship among the sides of a right triangle

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0
If it is a special triangle (either 45-45-90 or 30-60-90) then you select the tools from the rules of special triangles.  

Otherwise, if you know two angles and a side of the triangle (AAS or ASA) you use law of sines.  If you know two sides and an angle (SSA) you can also use law of sines.

Use the law of cosines when you know two sides and the angle in between them (SAS).
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6 0
2 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
Please help i will make brainliest
NARA [144]
It is answer b!!! hope this helps
5 0
3 years ago
What’s the area of a rectangle measuring 13 inches x 12 in?
vitfil [10]
13 x 12 = 156 in<span>2 Hope I could help :)</span>
3 0
3 years ago
Help, please, I need help on this question.​
Inessa [10]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
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