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Virty [35]
3 years ago
11

Seventeen less than three times a number is less than four times the number decreased by nine.

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:  x > -8

Step-by-step explanation:

3x - 17 < 4x -  9   subtract 3x from both sides, and add 9 to both sides

<u> -3x + 9 < -3x + 9</u>

0  - 8   <  x  +  0      Rewrite and reverse the sign to simplify

     x > -8

     

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nancy spent 7/8 hour working out at the gym she spent 5/7 of that time lifting weights what fraction of an hour did sje spentld
Juli2301 [7.4K]

\frac{9}{56}\\ Fraction of hour was spent by NAncy in lifting weights

Step-by-step explanation:

Time spent at the gym by Nancy = \frac{7}{8}\,hour

Time spent at lifting weights =  \frac{5}{7}\,hour

What fraction of hour she spent in lifting weights?

Solving:

Fraction of hour she spent in lifting weights= Time spend at the gym-Time spent at lifting weights

Fraction of hour she spent in lifting weights=\frac{7}{8}\,hour-\frac{5}{7}\,hour

=\frac{49}{56}-\frac{40}{56}\\=\frac{49-40}{56}\\=\frac{9}{56}\\

So, \frac{9}{56}\\ Fraction of hour was spent by Nancy in lifting weights

Keywords: Word Problems involving Fractions

Learn more about Word Problems involving Fractions at:

  • brainly.com/question/1648978
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  • brainly.com/question/605571

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7 0
3 years ago
Six times a number is greater than 20 more than that number. Which are the possible values of that number?
Neporo4naja [7]
I don't know how to make a 'greater than' sign.

6x is greater than x + 20
6x - x is greater than 20
5x is greater than 20
x is greater than 20 divided by 5
x is greater than 4

So, any number greater than 4 will work in this equation.
4 0
3 years ago
Read 2 more answers
Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
3 years ago
Bobby is testing the effectiveness of a new cough medication. There are 100 people with a cough in the study. Seventy patients r
Tresset [83]

Answer:

0.665

Step-by-step explanation:

Given:  100 people are split into two groups 70 and 30.  I group is given cough syrup treatment but second group did not.

Prob for a person to be in the cough medication group = 0.70

Out of people who received medication, 34% did not have cough

Prob for a person to be in cough medication and did not have cough

=\frac{0.70(34)}{60}=0.397


Prob for a person to be not in cough medication and did not have cough

=\frac{0.3(20)}{30}=0.20

Probability for a person not to have cough

= P(M1C')+P(M2C')

where M1 = event of having medication and M2 = not having medication and C' not having cough

This is because M1 and M2 are mutually exclusive and exhaustive

SO P(C') = 0.397+0.2=0.597

Hence required prob =P(M1/C') = \frac{0.397}{0.597}=0.665

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3 years ago
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