For this case as MNOP is a square then the angles of each vertex are equal to 90 degrees.
Therefore, we have the following equations:
From these equations, we can clear the values of the unknowns.
For equation 1 we have:
For equation 2 we have:
Answer:
The values of t and f are given by:
9514 1404 393
Answer:
(x, y) = (-3, -13) or (-8, -23)
Step-by-step explanation:
The values for y can be equated and the resulting quadratic solved by factoring.
2x -7 = x^2 +13x +17
0 = x^2 +11x +24 . . . . . . subtract 2x-7
0 = (x +8)(x +3) . . . . . . . .factor*
The values of x that make these factors zero are x=-8 and x=-3. The corresponding values of y are ...
y = 2(-8) -7 = -23
y = 2(-3) -7 = -13
The solutions are ...
(x, y) = (-8, -23) and (-3, -13)
_____
* The constants in the binomial factors are factors of 24 that total 11. You know that ...
24 = 1×24 = 2×12 = 3×8 = 4×6
The sums of these factors are 25, 14, 11, 10. The factors 3 and 8 are the constants in the binomial factors of the quadratic.
"24" is the constant in the quadratic. "11" is the coefficient of the x term.
Answer:
The area of the clock
Step-by-step explanation:
We have been given the face of the clock that is
So that is also the circumference of the clock.
Since the clock is circular in shape.
So
From here we will calculate the value of radius of the clock that is circular in shape.
Then
Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.
Now
So the area of the face of the clock =
4.4a-7.3 is equal to
4.4a= 7.3 divide both sides by 4.4
a= 1.66
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B