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klasskru [66]
3 years ago
11

Quadratic functions. Linear, exponential, or a new kind of function? E and f?

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

e.

5^0 = 1; 5^1 = 5; 5^2 = 25; 5^(-1) = 1/5; 5^(-2) = 1/25

This is an exponential function since the exponent is a variable.

Function: f(x) = 5^x

Recursive: a_n = 5a_{n-1}

f.

Look at f(x) = x^2 for x = -2, -1, 0, 1, 2

f(-2) = 4

f(-1) = 1

f(0) = 0

f(1) = 1

f(2) = 2

Now look at the y-values in the table. They are the same we have here added to 5.

Your function is a quadratic function.

f(x) = x^2 + 5

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Answer: x = -2

Step-by-step explanation: To solve for <em>x</em>, in the equation you see here, our goal is to get <em>x</em> by itself.

Our first step will be to isolate the term containing <em>x</em> which in this case is 4x. To isolate 4x, we have to get rid of the +3 by subtracting 3 from both sides of the equation. On the left, +3 and -3 cancel out and we're left with 4x. On the right, -5 - 3 simplifies to -8.

Now we have the equation 4x = -8.

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F(3)=5 // f(3)=2(3)-1 = 5
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