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klasskru [66]
3 years ago
11

Quadratic functions. Linear, exponential, or a new kind of function? E and f?

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

e.

5^0 = 1; 5^1 = 5; 5^2 = 25; 5^(-1) = 1/5; 5^(-2) = 1/25

This is an exponential function since the exponent is a variable.

Function: f(x) = 5^x

Recursive: a_n = 5a_{n-1}

f.

Look at f(x) = x^2 for x = -2, -1, 0, 1, 2

f(-2) = 4

f(-1) = 1

f(0) = 0

f(1) = 1

f(2) = 2

Now look at the y-values in the table. They are the same we have here added to 5.

Your function is a quadratic function.

f(x) = x^2 + 5

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A) our null hypothesis is at p = 0.6

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This can be expressed in reference to the question as;

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Also;

P(x > 260) = z = (260 - 240)/9.8 = 2.04

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B) Type II error occurs when we fail to reject the null hypothesis even though it's false.

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Thus;

μ = np

μ = 400 × 0.48 = 192

Standard deviation is given by;

σ = √npq

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σ = √(400 × 0.48 × 0.52)

σ = √99.84

σ = 9.992

Type II error would be given by;

β = [((x1¯ - μ)/σ) < z > ((x2¯ - μ)/σ)]

β = [((220 - 192)/9.992) < z > ((260 - 192)/9.992)]

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