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klasskru [66]
3 years ago
11

Quadratic functions. Linear, exponential, or a new kind of function? E and f?

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

e.

5^0 = 1; 5^1 = 5; 5^2 = 25; 5^(-1) = 1/5; 5^(-2) = 1/25

This is an exponential function since the exponent is a variable.

Function: f(x) = 5^x

Recursive: a_n = 5a_{n-1}

f.

Look at f(x) = x^2 for x = -2, -1, 0, 1, 2

f(-2) = 4

f(-1) = 1

f(0) = 0

f(1) = 1

f(2) = 2

Now look at the y-values in the table. They are the same we have here added to 5.

Your function is a quadratic function.

f(x) = x^2 + 5

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For some integer n, the first, the third and the fifth terms of an arithmetic sequence are respectively 3n, 5n – 6, and 11n + 8.
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Answer:

a₄=8n+1= -39.

Step-by-step explanation:

1) if a₁=3n; a₃=5n-6 and a₅=11n+8, then it is possible to calculate the difference according to 0.5(a₅-a₃)=0.5(a₃-a₁). Then

2) 0.5(11n+8-5n+6)=0.5(5n-6-3n); ⇔ 6n+14=2n-6; ⇔ n= -5.

3) if n=-5, then the 4th term is:

a_4=\frac{a_5+a_3}{2}; \ = > \ a_4=\frac{11n+8+5n-6}{2}=8n+1;

or a₄=-39.

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Can someone explain to me how to do this exercise?
kolbaska11 [484]
Hi
You should put into them.I mean
1-This is 2 part.First, you should put f(-1) then you should put what you found.
Solve is:f(-1)=3(-1)-2(-1)^2 so -3-2=-5 then put in other one:if f(-5):-15-50=-65
Is it correct? 
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Step-by-step explanation:


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