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4 years ago

AWSWER QUICK WILL GIVE 25+ BRAINLIEST

Mathematics

2 answers:

Andrej [43]4 years ago

8 0

Answer:

(-6,-2)

Step-by-step explanation:

if you substitute y=-1/3x-4 into the first equation and simplify you get x=-6. then you substitute -6 into y=-1/3x-4 and get y=-2

MAVERICK [17]4 years ago

6 0

your answer would be A. (–6, –2)

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What is the solution set?

evablogger [386]

x>9
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I used MathPapa to get the answer

5 0

3 years ago

Margaret is thinking of a number. She says, “My number is odd. It is a factor of 36 and a multiple of 3” There are two possible

Novay_Z [31]

Answer:

3,9

Step-by-step explanation:

Factors of 36 = 1,2,3,4,6,9,12,18,36

Those factors which are odd = 1,3,9

Odd Factors which are multiple of 3 = 3,9

So, these are the two numbers Margret might be thinking of.

4 0

4 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Find product for each question, and show reasoning a - (2.5) x (1.4) b - (0.64) x (0.81) If you do answer, thanks alot! Have a g

Dennis_Churaev [7]

Answer:

-3.50

-0.5184

Step-by-step explanation:

The product :

. A.)

- 2. 5 * 1.4

-2.5

*1. 4

____

100

____

-3.50

____

B.)

-0.64

*0.81

______

___064

__512

_000

________

-0.5184

_______

7 0

3 years ago

Write an equation for the line in slope-intercept form.

avanturin [10]

Answer:

y=2

Step-by-step explanation:

8 0

3 years ago