All categories

2 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics

2 answers:

Scilla [17]2 years ago

6 0

Answer:

I'd think that it would be C. 2/6

Step-by-step explanation:

Count the lines between 0 and 1. The dot falls on the second line out of 6 (6/6 being 1). Hopefully this helps, good luck :)

neonofarm [45]2 years ago

5 0

C ⠀ ⠀ ⠀ ⠀ ⠀

The points between 0 and 1 increase in increments of 1/6th

You might be interested in

Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.

const2013 [10]

Answer:

$T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

Step-by-step explanation:

Remember that for any curve $r(t)$

The tangent vector is given by

$T(t) = \frac{r'(t) }{| r'(t)| }$

And the normal vector is given by

$N(t) = \frac{T'(t)}{|T'(t)|}$

For this case, using the chain rule

$r'(t) = ( -10*2tsin(t^2) , 102t cos(t^2) )\\$

And also remember that

$|r'(t)| = \sqrt{(-10*2tsin(t^2))^2 + ( 10*2t cos(t^2) )^2} \\\\ = \sqrt{400 t^2*( sin(t^2)^2 + cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t$

Therefore

$T(t) = r'(t) / |r'(t) | = ( -10*2tsin(t^2) , 10*2t cos(t^2) )/ 20t\\\\ = ( -10*2tsin(t^2)/ 20t , 10*2t cos(t^2) / 20t )\\= ( -sin(t^2), cos(t^2) )$

Similarly, using the quotient rule and the chain rule

$T'(t) = ( -2t cos(t^2) , -2t sin(t^2))$

And also

$|T'(t)| = \sqrt{ ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t$

Therefore

$N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

Notice that

1. $|N(t)| = |T(t) | = \sqrt{ cos(t^2)^2 + sin(t^2)^2 } = \sqrt{1} = 1$

2. $N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0$

Simlarly

$r'(t) = (2t,-6,0) \\$

and

$|r'(t)| = \sqrt{(2t)^2 + 6^2} = \sqrt{4t^2 + 36}$

Therefore

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

Then

$T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)$

and also

$|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 + ( (3 t)/(9 + t^2)^{3/2})^2 + 0^2 }\\= 3/(t^2 + 9 )$

And since

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

6 0

2 years ago

Cómo se resuelve la ecuación raíz cuadrada (×) -4=8

denis23 [38]

X=12 that's is the answers

4 0

2 years ago

0.56 as a fraction in simplest form.

Vlada [557]

Answer:

14/25

Step-by-step explanation:

0.56=56/100=28/50=14/25

4 0

2 years ago

Find the values of x and y using the give chord, secant, and tangent lengths

garri49 [273]

Answer: 7

Step-by-step explanation:

3 0

3 years ago

Nola purchased 2.5 pounds of cheese for 10.50. Her mother purchased 3pounds of the same cheese for$12.60. The cost of cheese var

Dennis_Churaev [7]

Answer:

cost per pound = $4.20

Step-by-step explanation:

Cheese cost per pound = ?

first for the cost per pound

cost per pound = total cost / pounds bought

cost per pound = $10.50 / 2.5 pounds

cost per pound = $4.20

to check the above answer is correct

cost per pound = total cost / pounds bought

cost per pound = $12.60 / 3 pounds

cost per pound = $4.20

Therefor, the cheese costs $4.20 per pound.

5 0

2 years ago