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sashaice [31]
3 years ago
15

What happens to the equilibrium when the pressure increased

Chemistry
2 answers:
Nesterboy [21]3 years ago
7 0
When a reversible reaction is occurring and the pressure is increased then the equilibrium which is dynamic will shift in order to facilitate this change by virtue of Le Chatelier's principle.  When pressure is increased, the equilibrium shifts to favor the side with the most number of moles.

For example, the theoretical formation of ammonia is characterized by the reaction:   N₂   +   3H₂    ⇆   2NH₃ 
If the pressure is increased in this reaction system, then the equilibrium would shift to the left, since that side has three moles of hydrogen and one mole of nitrogen for a total of four moles while the right side only has two moles.
denpristay [2]3 years ago
3 0

Answer:

Position of equilibrium changes with increase in pressure but equilibrium constant remains same

Explanation:

For a reaction - A(g)\rightleftharpoons 2B(g), equilibrium shifts toward left with increase in pressure.

Because, number of gas molecules increases in forward direction which means pressure increases in forward direction. According to Le-chatlier principle, equilibrium will shift toward backward direction or towards left to minimize the increased pressure as well as keep the equilibrium constant same.

For a reaction- 2B(g)\rightleftharpoons A(g), equilibrium shifts toward right with increase in pressure.

Explanation for this is same as above.

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Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance
Scrat [10]

Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance?


1. NaCl(aq) and LiNO3(aq)

2. KCl(aq) and AgNO3(aq)  answer

3. KCl(aq) and LiCL(aq)

4. NaNO3(aq) and AgNO3(aq)


2 is the answer because AgCl is formed and that is a white ppt.

5 0
3 years ago
Read 2 more answers
A mixture of 454 kg of applesauce at 10 degrees Celsius is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet
stira [4]

Explanation:

The given data is as follows.

           Mass of apple sauce mixture = 454 kg

           Heat added (Q) = 121300 kJ

 Heat capacity (C_{p}) of apple sauce at 32.8^{o}C = 4.0177 kJ/kg^{o}C

So, Heat given by heat exchanger = heat taken by apple sauce

                            Q = mC_{p} \Delta T

or,                    Q = mC_{p} (T_{f} - T_{i})  

Putting the given values into the above formula as follows.

                     Q = mC_{p} (T_{f} - T_{i})  

              121300 kJ = 454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)

                      T_{f} = 76.5^{o}C

Thus, we can conclude that outlet temperature of the apple sauce is 76.5^{o}C.

3 0
4 years ago
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
3 years ago
If all the water in 430.0 mL of a 0.45 M NaCI solution evaporates what is the mass of NaCI will remain
skad [1K]

Answer:

11.31 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).</em>

<em></em>

<em>∴ mass of NaCl remained after evaporation of water = (M)(V of the solution (L))(molar mass)</em> = (0.45 M)(0.43 L)(58.44 g/mol) = <em>11.31 g.</em>

6 0
3 years ago
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LOOK AT THE PICTURE!! i’ll mark as brainliest!!
Lera25 [3.4K]

Answer:

c

Explanation:

8 0
3 years ago
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