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sashaice [31]
3 years ago
15

What happens to the equilibrium when the pressure increased

Chemistry
2 answers:
Nesterboy [21]3 years ago
7 0
When a reversible reaction is occurring and the pressure is increased then the equilibrium which is dynamic will shift in order to facilitate this change by virtue of Le Chatelier's principle.  When pressure is increased, the equilibrium shifts to favor the side with the most number of moles.

For example, the theoretical formation of ammonia is characterized by the reaction:   N₂   +   3H₂    ⇆   2NH₃ 
If the pressure is increased in this reaction system, then the equilibrium would shift to the left, since that side has three moles of hydrogen and one mole of nitrogen for a total of four moles while the right side only has two moles.
denpristay [2]3 years ago
3 0

Answer:

Position of equilibrium changes with increase in pressure but equilibrium constant remains same

Explanation:

For a reaction - A(g)\rightleftharpoons 2B(g), equilibrium shifts toward left with increase in pressure.

Because, number of gas molecules increases in forward direction which means pressure increases in forward direction. According to Le-chatlier principle, equilibrium will shift toward backward direction or towards left to minimize the increased pressure as well as keep the equilibrium constant same.

For a reaction- 2B(g)\rightleftharpoons A(g), equilibrium shifts toward right with increase in pressure.

Explanation for this is same as above.

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the components of the pure substance will not be able to be separated by physical means


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3 years ago
Using the Periodic Table, predict which elements will have similar chemical properties or reactivity
tekilochka [14]

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Explanation:

6 0
3 years ago
Consider the following balanced equation for the following reaction:
balandron [24]

<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 47.48 grams

<u>Explanation:</u>

For the given chemical equation:

15O_2(g)+2C_6H_5COOH(aq.)\rightarrow 14CO_2(g)+6H_2O(l)

To calculate the actual yield of carbon dioxide, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Percentage yield of carbon dioxide = 83 %

Theoretical yield of carbon dioxide = 1.30 moles

Putting values in above equation, we get:

83=\frac{\text{Actual yield of carbon dioxide}}{1.30moles}\times 100\\\\\text{Actual yield of carbon dioxide}=\frac{1.30\times 83}{100}=1.079moles

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.079 moles

Putting values in above equation, we get:

1.079mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.079mol\times 44g/mol)=47.48g

Hence, the amount of carbon dioxide formed in the reaction is 47.48 grams

8 0
4 years ago
Match the factors which affect the rate of dissolving/dissociation/diffusion.
aev [14]

Answer:

Increased surface area - finely divided solute

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4 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
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Answer:

58.92 g EDTA

Explanation:

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.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
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