Question

What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol

Answer 1

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x 0.5 mol EDTA  x  374 g EDTA  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA