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1 year ago

What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol

Chemistry

1 answer:

statuscvo [17]1 year ago

4 0

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L

M = Moles / Liter

.3151 L x <u>0.5 mol EDTA</u> x <u>374 g EDTA</u> = 58.92 g EDTA

1 L EDTA 1 mol EDTA

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A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?

dem82 [27]

Answer: $1.67\times 10^{-3}$

Explanation:

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$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

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Putting in the values we get:

Also $pH=-log[H^+]$

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$[H^+]=0.01$

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$K_a=1.67\times 10^{-3]$

Thus the vale of $K_a$ for the acid is $1.67\times 10^{-3}$

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3 years ago

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elixir [45]

Answer:

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Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.

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MissTica

Answer:4 M

Explanation:google

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Answer:

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