All categories

2 years ago

What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol

Chemistry

1 answer:

statuscvo [17]2 years ago

4 0

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L

M = Moles / Liter

.3151 L x 0.5 mol EDTA x 374 g EDTA = 58.92 g EDTA

1 L EDTA 1 mol EDTA

You might be interested in

Plant and animal cells contain many of the same structures, and those structures carry out the same functions in both types of c

777dan777 [17]

The answer is A because I know the answer

4 0

2 years ago

Consider the conversion of 2-naphthol and 1-bromobutane into an ether via the williamson ether synthesis. list the procedural st

Lemur [1.5K]

Answer:

Following are the solution to this question:

Explanation:

Please find the complete question in the attachment.

Start of Laboratory

Dissolve 2-naphthol in the round bottom flask with ethanol.

Add pellets of sodium hydroxide and hot chips. Attach a condenser.

Heat for 20 minutes under reflux, until the put a burden dissolves.

After an additional hour, add 1-Bromobutane and reflux.

Pour the contents into a beaker with ice from a round bottom flask.

On a Bachner funnel, absorb the supernatant by vacuum filtration.

Utilizing cold water to rinse the material and dry that on the filter.

Ending of the Lab

6 0

3 years ago

What physical property difference enabled you to Seperate salt from water?

elena55 [62]

The two techniques for separating an insoluble solid from a liquid are filtration and centrifuging. Filtration relies on the fact that the solid particles are smaller than the filter paper pores which allow the tiny molecules of liquid to pass through. With solids which dissolve in a liquid solvent, evaporation is commonly used to recover the solid and distillation is used to recover the solvent.

5 0

2 years ago

Read 2 more answers

What is [h3o ] in a solution of 0.075 m hno2 and 0.030 m nano2?

Tanya [424]

Answer is: concentration of hydrogenium ions is 9,54·10⁻⁵ M.
c(HNO₂) = 0,075 M.
c(NaNO₂) = 0,035 M.
Ka(HNO₂) = 4,5·10⁻⁵.
This is buffer solution, so use Henderson–Hasselbalch equation:
pH = pKa + log(c(NaNO₂) ÷ c(HNO₂)).
pH = -log(4,5·10⁻⁵) + log(0,035 M ÷ 0,075 M).
pH = 4,35 - 0,33.
pH = 4,02.
[H₃O⁺] = 10∧(-4,02).
[H₃O⁺] = 0,0000954 M = 9,54·10⁻⁵ M.

8 0

3 years ago

What is the volume of an object that has a mass of 3.5 grams and has a density of 2.50 g/mL? Include units and proper sig figs l

jolli1 [7]

1.4mL

Explanation:

Given parameters:

Mass of object = 3.5g

density = 2.5g/mL

Unknown:

Volume of the object = ?

Solution: