Answer:
they could collide 241.66 molec / in² by increasing the volume to 40.2L
Explanation:
ideal gas:
<u>Boyle Law</u>: at constant temperature the pressure of a gas varies inversely with the volume
- V1 * P1 = V2 * P2
- P = F / A
∴ V1 = 6.70 L;
∴ P1 = 1450 molec / in²
∴ V2 = 40.2 L
⇒ P2 = (( 6.70 L ) * ( 1450 molec/in²)) / 40.2 L
⇒ P2 = 241.66 molec/in²
1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.
Thank you for posting your question here. I hope my answer will help. below are the choices that can be found elsewhere:
a. 300 mi/hr2
<span>b. 61 mi/hr2 </span>
<span>c. 8,201 mi/hr2 </span>
<span>d. 40,500 mi/hr
</span>
Below is the solution:
<span>135 * 135 / 0.450 = 40,500 mi/hr2 </span>
Food web should be the correct answer
:)
Answer:
Kp = P(SO2) * P(O2) / P(SO3)
Explanation:
The equation is given as;
SO3(g) --> SO2(g) + O2(g)
In the pressurer equilibrium constant expression, only the gaseous entities are considered.
It is given as;
Kp = P(products) / P(reactants)
Product are SO2(g) and O2(g)
Reactant is SO3(g)
Kp = P(SO2) * P(O2) / P(SO3)
