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2 years ago

write chemical equations of photosynthesis and cellular respiration and show if carbon is oxidized or reduced

Chemistry

1 answer:

irina [24]2 years ago

6 0

Answer:

Explanation:

The chemical reaction for cellular respiration is as follows -

C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) + 38 ATP molecules ( Energy ) .

This is an example of oxidation of carbon .

The chemical reaction for photosynthesis is as follows -

6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂ ( Oxygen ).

This is an example of reduction of carbon .

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Calculate the molar mass of a gaseous substance if 0.125 g of the gas occupies 93.3 mL at STP.

just olya [345]

Answer:

30.0g/mol

Explanation:

Step 1: Given data

Mass of the gas: 0.125 g

Pressure (P): 1 atm (standard pressure)

Temperature (T): 273.15 K (standard temperature)

Volume (V): 93.3 mL

Step 2: Calculate the moles of the gas

We will use the ideal gas equation.

$P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{1atm \times 0.0933L}{\frac{0.0821atm.L}{mol.K} \times 273.15K} = 4.16 \times 10^{-3} mol$

Step 3: Calculate the molar mass of the gas

4.16 × 10⁻³ moles correspond to a mass of 0.125 g. The molar mass of the gas is:

$\frac{0.125g}{4.16 \times 10^{-3} mol} =30.0g/mol$

7 0

2 years ago

Whats the answer giving brainliest :)

MissTica

It’s is c, if you oook it’s the only clear answer

5 0

2 years ago

HELP THIS IS SCIENCE I HAVING TROUBLE

muminat

Answer:

1/2 of the way down

Explanation:

8 0

2 years ago

Read 2 more answers

How many liters are in a .00813M solution that contains 1.55 g of KBr?

Sloan [31]

Answer:

1.602 L (or) 1602 mL

Explanation:

Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution ----- (1)

Rearranging above equation for volume,

Volume of solution = Moles / Molarity -------(2)

Data Given;

Molarity = 0.00813 mol.L⁻¹

Mass = 1.55 g

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 1.55 g / 119.002 g.mol⁻¹

Moles = 0.0130 mol

Now, putting value of Moles and Molarity in eq. 2,

Volume of solution = 0.0130 mol / 0.00813 mol.L⁻¹

Volume of solution = 1.60 L

or,

Volume of solution = 1602 mL

5 0

2 years ago

Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr

ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

$=\frac{x^2}{0.02 -x}$

$=8.32 \times 10^{-9}$

Clearing $x$ , we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

3 0

2 years ago