I think the answer may be d I'm not completely sure
Answer:HERE IS YOUR ANSWER
THE POINTS ARE
IF WE PUT THE OBJECT BETWEEN THE FOCUS
AND THE POLE
THEN THE IMAGE FORMED WILL be MAGNIFIED
If that’s not what you are looking for, try this one:
For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.
Given here the "size of the image" is twice to that of the object.
Hence, it is consider that the magnification is +2.
So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."
Explanation:
Explicacion
m = 65 kg
g = 10 m/s²
r = 0.5 cm (1m / 100 cm) = 0.05 m
A = π r² = π (0.05 m)² = 0.00785 m²
F =W = m g = 65 kg(10 m/s²) = 650 N
P = F/A = 650 N / 0.00785 m² = 82802.54 N/m²
let me know!! i need the same answer,
Momentum = Mass x Velocity
Put the values where they belong and solve for Velocity.
In this case, since Mass is being multiplied by Velocity, to solve for be Velocity you would divide both sides by Velocity. The velocity will equal the momentum divided by the mass.
