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Anvisha [2.4K]
3 years ago
9

Using two billiard balls, in 3-4 sentences, design an experiment to demonstrate the law of conservation of momentum.

Physics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

In the explanation

Explanation:

<u>Experiment</u>:

Consider two billiard balls of masses ‘m₁’ and ‘m₂’, moving with velocities ‘u₁’ and ‘u₂’, respectively,  such that u₁ is greater than u₂. After some time, these balls collide with each other and their velocities  become ‘v₁’ and ‘v₂’, respectively.

<u>Observation</u>:

The masses of balls should be measured and their initial and final velocities should be measured.

<u>Result</u>:

In order to prove law of conservation of moment following equation must be satisfied by observed values:

Total\ Momentum\ Before\ Collision = Total\ Momentum\ After\ Collision\\\\m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}

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1. If an object that stands 3 centimeters high is placed 12 centimeters in front of a plane
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Answer:

1. 12 cm

2. 0.133 m

3. 0.03 m

4. Plane mirror

Virtual image

Upright

Behind the mirror

The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Real image

Inverted image

In front of the the mirror

Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Virtual image

Upright image

Behind the the mirror

Enlarged

Convex mirror

Type = Virtual image

Appearance = Upright image

Placement = Behind the mirror

Size = Smaller than the object

Explanation:

1. For plane mirror, since there is no magnification, the virtual image distance from the mirror = object distance from the mirror = 12 cm behind the mirror

2. The height of the object = 0.3 m

The distance of the object from the mirror = 0.4 meters

Height of image formed = 0.1 meter

We have;

Magnification, \ m = \dfrac{Image \ height }{Object \ height } = \dfrac{Image \ distance \ from \ mirror }{Object\ distance \ from \ mirror }

m = \dfrac{0.1}{0.3 } = \dfrac{Image \ distance \ from \ mirror }{0.4 }

Image distance from the mirror = 0.1/0.3×0.4 = 2/15 = 0.133 m

Image distance from the mirror = 0.133 m

3. m = \dfrac{Image \ height}{0.10 } = \dfrac{0.06 }{0.20 }

The image height = 0.06/0.2×0.1 = 3/100 = 0.03 meter

The image height = 0.03 meter

4. Plane mirror

Type = Virtual image

Appearance = Upright image with the left transformed to right

Placement = Behind the mirror

Size = The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Type = Real image

Appearance = Inverted image

Placement = In front of the the mirror

Size = Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Type = Virtual image

Appearance = Upright image

Placement = Behind the the mirror

Size = Enlarged

Convex mirror

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