Answer:
Explanation:
you mean deceleration right ? because the acceleration is 250m/s
Answer:
d. 6.0 m
Explanation:
Given;
initial velocity of the car, u = 7.0 m/s
distance traveled by the car, d = 1.5 m
Assuming the car to be decelerating at a constant rate when the brakes were applied;
v² = u² + 2(-a)s
v² = u² - 2as
where;
v is the final velocity of the car when it stops
0 = u² - 2as
2as = u²
a = u² / 2s
a = (7)² / (2 x 1.5)
a = 16.333 m/s
When the velocity is 14 m/s
v² = u² - 2as
0 = u² - 2as
2as = u²
s = u² / 2a
s = (14)² / (2 x 16.333)
s = 6.0 m
Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.
The correct option is d
Answer:
Health-related physical fitness is primarily associated with disease prevention and functional health.
Explanation:
This is ur answer actually I just took it from Go ogle
Explanation:
<u>Using Equations of Motion</u> :
(1) v = u + at
24 = 6.5 + a * 210
<u>a (Acceleration) = 0.083 m/s^2 </u>
<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS
S = 576 - 42.25 / 0.166
<u>S (Distance travelled) = 3215.3 m </u>
(Option A seems a typo since the answer is 3215.3 m)
