Energy is conserved. If the ball reaches a height of 5.50 m, it has gained a certain amount of gravitational potential energy. That energy had to come from somewhere. From this fact, you can deduce the speed of the ball at the end of the impact with the racket.
<h3>What is
gravitational potential energy?</h3>
Gravitational energy or gravitational potential energy is the potential energy a huge item has corresponding to one more monstrous article because of gravity. It is the potential energy related with the gravitational field, which is delivered (changed over into active energy) when the articles fall towards one another. Gravitational potential energy increments when two articles are brought further apart. It is the potential energy related with the gravitational field, which is delivered (changed over into dynamic energy) when the items fall towards one another. Gravitational potential energy increments when two items are brought further separated.
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Answer:
Explanation:
Given
Velocity of traffic 
Maximum value of Centripetal force is one-tenth of weight
such that 
to make a safe turn centripetal force with radius of curvature r is given by






Answer:
5.6 Tesla
Explanation:
L = 52 cm = 0.52 m
V = 2.75 m/s
e = 8 V
Let B be tha magnitude of magnetic field. Use the formula for the motional emf
e = B × V × L
B = e / V L
B = 8 / (2.75 × 0.52)
B = 5.6 Tesla
Yes it can be seen from space. If you go on NASA'S website you can get a bunch of info on how it looks from space
Answer:
5.4 × 10⁸ W/m²
Explanation:
Given that:
The Power (P) of Betelgeuse is estimated to release 3.846 × 10³¹ W
the mass of the exoplanet = 5.972 × 10²⁴ kg
radius of the earth = 1.27 × 10⁷ m
half the distance (i.e radius r ) = 7.5 × 10¹⁰ m
a) What is the intensity of Betelgeuse at the "earth’s" surface?
The Intensity of Betelgeuse can be determined by using the formula:


I = 544097698.8 W/m²
I = 5.4 × 10⁸ W/m²