40000=5000e^30r
40000/5000=e^30r
R=(log(40000/5000)/log(e))/30)*100
R=6.93%
Answer:
21 ways
Step-by-step explanation:
a, b, c, d, e, f, g, linda
1 2 linda
a__ b__ __
a__c __ __
a__d __ __
a__ e__ __
a__ f__ __
a__ g__ __
b__c __ __
b__d __ __
b__ e__ __
b__ f__ __
b__ g__ __
c__d __ __
c__ e__ __
c__ f__ __
c__ g__ __
d__ e__ __
d__ f__ __
d__ g__ __
e__ f__ __
e__ g__ __
f__ g__ __
count them
in total
there are
21 triples
Answer:
2
Step-by-step explanation:
are you siruous
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032