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3 years ago

Hey! i’ll give brainliest please help

Mathematics

1 answer:

netineya [11]3 years ago

8 0

Answer:

The last one looks correct

Step-by-step explanation:

Because if they have stronger winds then that would improve their flight making them get use to it, and will for sure get stronger over time

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What is the value of the 5 in the number 975,178

maxonik [38]

It’s in the thousands place

3 0

4 years ago

Read 2 more answers

1. Simplify. 4(2a - 1) - 4 + 7a

daser333 [38]

Answer:

=15a−8

Step-by-step explanation:

Let's simplify step-by-step.

4(2a−1)−4+7a

Distribute:

=(4)(2a)+(4)(−1)+−4+7a

=8a+−4+−4+7a

Combine Like Terms:

=8a+−4+−4+7a

=(8a+7a)+(−4+−4)

=15a+−8

Answer:

=15a−8

hope i helped

-lvr

4 0

3 years ago

I need help on 5 and 6 please HELP ME

morpeh [17]

480 breaths in 2 minutes

8 0

3 years ago

Please help with number 11 please.

Tomtit [17]

Answer: 4/10

Step-by-step explanation:

2/5 = ?/10 As the amount of pieces correspond to the denominator

As 5x2 = 10

2x2 = 4

5 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago