An ice cube is dropped into boiling water. How will heat flow between the water and the ice cube?

2 answers:

7 0

Heat transfers from hot body to cold body. So when ice is dropped in water , the water at higher temperature will lose heat energy and is gained by the ice at less temperature. When the Net heat lost equals to Net heat gained i.e.,When both the bodies attain themal equilibrium, the flow of heat energy stops and both attain equal temperatures.

Natasha2012 [34]3 years ago

4 0

On a microscopic (molecular) level, heat flows from the ice to the boiling water
at a minuscule rate, and from the water to the ice at a humongous rate.

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For the reaction 2 NO(g) + 2 H2(g) => N2(g) + 2 H2O(g) the following data were collected. What is the rate law for this react

harkovskaia [24]

<u>Answer:</u> The rate law expression for the given reaction is written below.

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2NO(g)+2H_2(g)\rightarrow N_2(g)+2H_2O(g)$