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3 years ago

An ice cube is dropped into boiling water. How will heat flow between the water and the ice cube?

2 answers:

7 0

Heat transfers from hot body to cold body. So when ice is dropped in water , the water at higher temperature will lose heat energy and is gained by the ice at less temperature. When the Net heat lost equals to Net heat gained i.e.,When both the bodies attain themal equilibrium, the flow of heat energy stops and both attain equal temperatures.

Natasha2012 [34]3 years ago

4 0

On a microscopic (molecular) level, heat flows from the ice to the boiling water
at a minuscule rate, and from the water to the ice at a humongous rate.

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Which of the following are functions of the ears?

Advocard [28]

The functions of the ears are:

I. Hearing by collecting and processing sound waves

II. Keeping our balance when we turn or bend over; option A

<h3>What is the function of the ear?</h3>

The ear is one of the five sense organs in the body.

The sense organs are the organs which receive external stimulus and send it to the brain for processing and response.

The other sense organs are:

the eye
the nose
the skin
the tongue

The functions of the ear are for hearing and for balance.

In conclusion, the sense organs function to receive stimulus and send them to the brain.

Learn more about the functions of the ear at: brainly.com/question/924275

#SPJ1

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1 year ago

35.0 grams of nitrogen gas reacts with 60.0 grams of hydrogen gas: N2 + 3H2--> 2NH3

Misha Larkins [42]

Explanation:

Moles of N2 = 35.0g / (28g/mol) = 1.25mol

Moles of H2 = 60.0g / (2g/mol) = 30.0mol

Since 1.25mol * 3 < 30.0mol, nitrogen is limiting.

Moles of NH3 = 1.25mol * 2 = 2.50mol.

Mass of NH3 = 2.50mol * (17g/mol) = 42.5g.

30.0mol - 1.25mol * 3 = 26.25mol.

Excess mass of H2

= 26.25mol * (2g/mol) = 52.5g.

6 0

3 years ago

Can A fire extinguisher kill A Human Being

skad [1K]

Yes. it could kill someone because they are designed to take the oxygen out of the atmosphere to put out a fire, You can kill a person by suffixation, You can purchase a unit that gives off a harmless vapor that resembles white smoke though.

3 0

2 years ago

Read 2 more answers

Use the reaction below to balance the nuclear reaction equation.

Temka [501]

Answer:

neon-22

Explanation:

i got it right..have a great day.Jesus loves you<3

4 0

2 years ago

Read 2 more answers

Be sure to answer all parts. one of the most important industrial sources of ethanol is the reaction of steam with ethene derive

lions [1.4K]

Answer: 2.17x10⁻³ atm

Explanation:

First, we must write the balanced chemical equation for the process:

C₂H₄(g) + H₂O(g) ⇌ C₂H₅OH(g)

The chemical reactions that occur in a closed container can reach a state of <u>chemical equilibrium</u> that is characterized because the concentrations of the reactants and products remain constant over time. The <u>equilibrium constant</u> of a chemical reaction is the value of its reaction quotient in chemical equilibrium.

The equilibrium constant (K) is expressed as <u>the ratio between the molar concentrations (mol/L) of reactants and products.</u> Its value in a chemical reaction depends on the temperature, so it must always be specified.

<u>We will use the the equilibrium constant Kc of the reaction to calculate partial pressure of ethene.</u> The constant Kc for the above reaction is,

Kc = $\frac{[C_{2} H_{5}OH]}{[H_{2}O][C_{2} H_{4}]}$

According to the law of ideal gases,

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the gas constant (0.082057 atm L / mol K) .

We can use the ideal gas law to determine the molar concentrations ([x] = n / V) from the gas pressures of ethanol and water, assuming that all gases involved behave as ideal gases. In this way,

PV = nRT → P = (n/V) RT → P = [x] RT → [x] = P / RT

So,

$[C_{2} H_{5}OH] = \frac{200 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 4.06 \frac{mol}{L}$

$[H_{2}O] = \frac{400 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 8.12 \frac{mol}{L}$

So, the molar concentration of ethene (C₂H₄) will be,

$[C_{2} H_{4}] = \frac{[C_{2} H_{5}OH]}{[H_{2}O] x Kc} = \frac{4.06 \frac{mol}{L} }{8.12 \frac{mol}{L}x9.00 x 10^{3} \frac{L}{mol} } = 5.56 x 10^{-5}\frac{mol}{L}$

Then, according to the law of ideal gases,

$P_{C_{2} H_{4}} = [C_{2} H_{4}]RT = 5.56 x 10^{-5} \frac{mol}{L} x 0.082057 \frac{atm L}{mol K} x 600 K = 2.17x10^{-3} atm$

So, when the partial pressure of ethanol is 200 atm and the partial pressure of water is 400 atm, the partial pressure of ethene at 600 K is 2.17x10⁻³ atm.

7 0

3 years ago