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mario62 [17]
3 years ago
9

How does one determine the number of core electrons an atom has?

Chemistry
2 answers:
scoundrel [369]3 years ago
4 0

Answer: Subtract the number of valence electrons(outer most shell electrons) from the atomic number of an atom.

Explanation: The total number of electrons for an atom equals to its atomic number. Electrons are present in different shells. Electrons present in outer most shell(valence shell) are known as valence electrons and rest of the electrons present in inner shells are known as core electrons.

So, to determine the number of electrons we subtract the valence electrons from atomic number.

For example, atomic number of N (nitrogen) is 7. It has 5 valence electrons.

Number of core electrons for N = 7 - 5 = 2

Aleonysh [2.5K]3 years ago
3 0
Subtract the group number from the atomic number.
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What is the molar mass of sodium phosphate, Na3PO4?
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Answer:

164g

Explanation:

3×23+31+16×4

≈69+31+64

≈164.0 g

8 0
3 years ago
In the compound sodium methoxide (naoch3), there is ________ bonding
zvonat [6]
Maybe covalent bonding?
5 0
4 years ago
Complete and balance the molecular equation for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous barium nitrate, Ba(N
Rina8888 [55]

Answer:

1. The balanced molecular equation is given below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

2. The net ionic equation is given below:

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

Explanation:

1. The balanced molecular equation

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

The above equation can be balance as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaNO3 as shown below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

Now, the equation is balanced.

2. The bal net ionic equation.

This can be obtained as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —>

In solution, Na2SO4 and Ba(NO3)2 will dissociate as follow:

Na2SO4(aq) —> 2Na^+(aq) + SO4^2-(aq)

Ba(NO3)2(aq) —> Ba^2+(aq) + 2NO3^-(aq)

Na2SO4(aq) + Ba(NO3)2(aq) —>

2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) —> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)

Cancel the spectator ions i.e Na^+ and NO3^- to obtain the net ionic equation.

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

7 0
3 years ago
Which vein carries oxygenated blood back into the heart?
Finger [1]

Answer:

The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.

Explanation:

Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.

6 0
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Answer:

It’s A

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