1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
3 years ago
7

What is the molarity of a solution containing 55.8 g of mgcl2 dissolved in 1.00 l of solution?

Chemistry
2 answers:
viva [34]3 years ago
8 0

Answer:

0.587 M is the molarity of a solution.

Explanation:

Molarity=\frac{\text{mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (L)}}

Mass of magnesium chloride = 55.8 g

Molar mass of magnesium chloride = 95 g/mol

Volume of the solution = 1.00 L

Molarity of the solution :

=\frac{55.8 g}{95 g/mol\times 1.00 L}=0.587 M

0.587 M is the molarity of a solution.

MakcuM [25]3 years ago
7 0
The answer is 0.59 M.

Molar mass (Mr) of MgCl₂ is the sum of the molar masses of its elements.
So, from the periodic table:
Mr(Mg) = 24.3 g/l
Mr(Cl) = 35.45 g/l
Mr(MgCl₂) = Mr(Mg) + 2Mr(Cl) = 24.3 + 2 · 35.45 = 24.3 + 70.9 = 95.2 g/l

So, 1 mol has 95.2 g/l.

Our solution contains 55.8g in 1 l  of solution, which is 55.8 g/l

Now, we need to make a proportion:
1 mole has 95.2 g/l, how much moles will have 55.8 g/l:
1 M : 95.2 g/l = x : 55.8 g/l
x = 1 M · 55.8 g/l ÷ 95.2 g/l ≈ 0.59 M
You might be interested in
Bromine has two isotopes: 50.69% of Bromine has a mass number of 79 while 49.31% of Bromine has a mass number of 81. Calculate t
natka813 [3]
Not sure. How to answer this question.Look it up
8 0
3 years ago
Stephanie has been doing research on how petroleum is formed. She says that oxygen must be present while the tiny plants and ani
zimovet [89]

Stephanie is incorrect. Since fossil fuels form in the absence of oxygen, if oxygen is present, they cannot form.

(sample answer:)

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP- In the solid state, how does Water compare to Neon and Argon? Why do you think they act differently?
alekssr [168]
Neon and Argon are known as the noble gases. This means that there inert and don’t typically react. The noble gases have full outer shells and therefore satisfy the octet rule. Hydrogen, on the other hand, must lose an electron to become stable. That is why it reacts.
3 0
3 years ago
A 60.0 g block of iron that has an initial temperature of 250. °C and 60.0 g bloc of gold that has an initial temperature of 45.
Maslowich

Answer:

The final temperature at the equilibrium is 204.6 °C

Explanation:

Step 1: Data given

Mass of iron = 60.0 grams

Initial temperature = 250 °C

Mass of gold = 60.0 grams

Initial temperature of gold = 45.0 °C

The specific heat capacity of iron = 0.449 J/g•°C

The specific heat capacity of gold = 0.128 J/g•°C.

Step 2: Calculate the final temperature at the equilibrium

Heat lost = Heat gained

Qlost = -Qgained

Qiron = -Qgold

Q=m*c*ΔT

m(iron) * c(iron) *ΔT(iron) = -m(gold) * c(gold) *ΔT(gold)

⇒with m(iron) = the mass of iron = 60.0 grams

⇒with c(iron) = the specific heat of iron = 0.449 J/g°C

⇒with ΔT(iron)= the change of temperature of iron = T2 - T1 = T2 - 250.0°C

⇒with m(gold) = the mass of gold= 60.0 grams

⇒with c(gold) = the specific heat of gold = 0.128 J/g°C

⇒with ΔT(gold) = the change of temperature of gold = T2 - 45.0 °C

60.0 *0.449 * (T2 - 250.0) = -60.0 * 0.128 * (T2 - 45.0 )

26.94 * (T2 - 250.0) = -7.68 * (T2 - 45.0)

26.94T2 - 6735 = -7.68T2 + 345.6

34.62T2 = 7080.6

T2 = 204.5 °C

The final temperature at the equilibrium is 204.6 °C

5 0
3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
Other questions:
  • A gas-forming reaction produces 1.15 m 3 of gas against a constant pressure of 102.0 kPa. Calculate the work done by the gas in
    12·1 answer
  • In chemistry, we did a lab in which we had a certain mass of copper, performed multiple experiments on the copper, and at the en
    14·1 answer
  • What are the most chemically stable elements (in terms of reactivity) on the periodic table?
    10·1 answer
  • What type of a graph shows data as they are pieces of most of pie
    11·1 answer
  • Explain the relationship between heat and thermal energy
    7·2 answers
  • I need help writing a Christmas story about electricity
    12·1 answer
  • If an ion has 22 protons and 18 electrons, then what is its charge?
    15·2 answers
  • Science: Number 3 plsss
    8·2 answers
  • Como se explica o fato de o diamante e o grafite serem formados pelo mesmo elemento, o carbono, e serem materiais completamente
    7·1 answer
  • How much energy does it take to raise the temperature of 80g of aluminium 15 degree Celsius
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!