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pychu [463]
1 year ago
8

Urgent!! will give brainliest!!

Chemistry
1 answer:
Tamiku [17]1 year ago
8 0

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons.

<h3>What is an Arrhenius acid?</h3>

An Arrhenius acid increases the number ofH^+ ions in the water.

According to the Arrhenius theory, a substance which has hydrogen atom and can easily give hydrogen ion or proton in its aqueous solution is called as Arrhenius acid.

For example, when hydrochloric acid is dissolved in water, it forms chloride ion (Cl^-) and hydronium ion (H_3O^+).

Learn more about the Arrhenius acid here:

brainly.com/question/9936252

#SPJ1

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If you had a beaker full of black powder which of the following could you have?
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Answer:

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6 0
3 years ago
Fix the formula for KF2<br> Write out the full correct formula?
Korvikt [17]

Given :

A chemical compound KF_2 .

To Find :

Fix the formula for KF_2 and write the full correct formula.

Solution :

We know, Potassium( K ) and Fluorine( F ) both have a valency of 1 i.e potassium can donate one electron and Fluorine can accept one electron only.

So, the chemical formula KF_2 is wrong because no element has filled electron.

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7 0
2 years ago
Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 L of carbon dioxide at 20.0 °C and
swat32

Answer:

\%\ mass\ of\ CaCO_3=93.37\ \%

Explanation:

Given that:

Pressure = 791 mmHg

Temperature = 20.0°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (20 + 273.15) K = 293.15 K  

T = 293.15 K  

Volume = 100 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637 L.mmHg/K.mol  

Applying the equation as:

791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol  × 293.15 K  

⇒n of CO_2 produced =  0.0493 moles

According to the reaction:-

CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts

0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts

Moles of calcium carbonate reacted = 0.0493 moles

Molar mass of CaCO_3 = 100.0869 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0493\ mol= \frac{Mass}{100.0869\ g/mol}

Mass_{CaCO_3}=4.93\ g

Impure sample mass = 5.28 g

Percent mass is percentage by the mass of the compound present in the sample.

\%\ mass\ of\ CaCO_3=\frac{Mass_{CaCO_3}}{Total\ mass}\times 100

\%\ mass\ of\ CaCO_3=\frac{4.93}{5.28}\times 100

\%\ mass\ of\ CaCO_3=93.37\ \%

3 0
2 years ago
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