The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
1 1/2 or 3/2 because 1/2 divided by 1/3 is equal to that
Answer: 75975=57=575775857755+*(78487478)779895==58766945=-=578455=570570950=4364347
Step-by-step explanation:
Answer:
50,015
Step-by-step explanation:
The total of ratio units is 7+5+9 = 21. Of those at company A, that company donated 7, or 7/21 = 1/3 of the total. 1/3 × 150,045 = 50,015