So covert 4 minutes to seconds. Which would be 4 times 60 which would mean there would be 240 seconds. So you would multiply 15 x 240 = 3,600 feet. Then multiply 22 x 240 = 5,280 feet. 5,280 - 3,600 = 1,680 feet.
ANSWER:
Skateboarder B will have traveled 1,680 more feet over 4 minutes.
Length of AC is 5 I hope this helps I can’t think right right now so bare with me
Answer:6018
Step-by-step explanation:
Given Sequence

It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)


Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 


Sa= 1.64

(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!