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Alekssandra [29.7K]
4 years ago
7

How far will a freely falling object fall from rest in six seconds?

Physics
2 answers:
bija089 [108]4 years ago
5 0
Tabulate, then find the proper equation, then solve.

vi=0
vf=?
t=6s
a=g=9.8m/s²

vf=vi+at
vf=gt
vf= (find this yourself)
navik [9.2K]4 years ago
4 0
Here are two ways to do it:

<u>Way #1:</u>
-- You know that gravity accelerates things that are falling freely, adding 9.8 m/s to their speed every second.

-- After 6 seconds, an object that fell from rest winds up falling at (9.8 x 6) = 58.8m/s.

-- During that time, its average speed was 1/2(0 + 58.8) = 29.4 m/s .

-- In 6 seconds, at an average speed of 29.4 m/s, it covers (29.4 x 6) = <em>176.4meters</em>.

<u>Way #2:</u>
This way only works if you remember the formula for the distance covered during uniform acceleration.

             D  =  1/2 (acceleration) (time)²

Acceleration = gravity = 9.8 m/s²
Time  =  6 seconds

           D  =  1/2 (9.8) (6)²  =  <em>176.4 meters</em>.
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A 0.140-kg baseball is dropped from rest. It has a speed of 1.20 m/s just before it hits the ground, and it rebounds with an upw
irga5000 [103]

Answer:

22 N upward

Explanation:

From the question,

Applying newton's second law of motion

F = m(v-u)/t....................... Equation 1

Where F = Average force exerted by the ground on the ball, m = mass of the baseball, v = final velocity, u = initial velocity, t = time of contact

Note: Let upward be negative and downward be positive

Given: m = 0.14 kg, v = -1.00 m/s, u = 1.2 m/s, t = 0.014 s

Substitute into equation 1

F = 0.14(-1-1.2)/0.014

F = 0.14(-2.2)/0.014

F = 10(-2.2)

F = -22 N

Note the negative sign shows that the force act upward

6 0
4 years ago
What is the sound intensity level in decibels? Use the usual reference level of I0 = 1.0×10−12 W/m2.
jek_recluse [69]

Answer:

L = 130 decibels

Explanation:

The computation of the sound intensity level in decibels is shown below:

According to the question, data provided is as follows

I = sound intensity = 10 W/m^2

I0 = reference level = 1 \times 10-12 W/m^2

Now

Intensity level ( or Loudness)is

L = log10 \frac{I}{10}

L = log10 \frac{10}{1\times 10^{-12}}

L = log10 \times 1013

= 13 \times 1 ( log10(10) = 1)

Therefore  

L = 13 bel

And as we know that

1 bel = 10 decibels

So,

The  Sound intensity level is

L = 130 decibels

5 0
4 years ago
A basketball is thrown for a free throw at 10m/s an angle of 20 degrees, makes it into the hoop and lands on the ground. Find th
Kruka [31]

Answer:

2

Explanation:

because uWU

6 0
3 years ago
Read 2 more answers
__________________________ energy is the total kinetic energy of particles of matter. options: mechanical thermal electrical che
MissTica

Answer:

Thermal energy

Explanation:

I believe it is because the movement of particles has a connection with the temperature. Example: Since gas particles move very fast, it must be hot and freshly occurred through heating process.

7 0
4 years ago
A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1
ss7ja [257]

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

5 0
3 years ago
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