Answer:
i. +/- 1.43% and +/- 0.71% ii. +/- 0.33%
Explanation:
Answer:
Time period = 2.5 sec
Frequency = 0.4 Hz
Amplitude = 0.26 m
Maximum speed = 0.65
Explanation:
No. of oscillations = 14
Time = 35 sec
(a). Time period of oscillation
T = 2.5 sec
This is the time period.
(b). Frequency
f = 0.4 Hz
This is the frequency.
(c). Oscillation from one side to another side is 65 - 13 = 52 cm = 0.52 m
Hence amplitude
A = 0.26 m
This is the amplitude.
(d). The maximum speed
2 × 3.14 × 0.4 × 0.26
0.65
Answer: (a) α =
(b) For r≤R: B(r) = μ_0.
For r≥R: B(r) = μ_0.
Explanation:
(a) The current I enclosed in a straight wire with current density not constant is calculated by:
where:
dA is the cross section.
In this case, a circular cross section of radius R, so it translates as:
For these circunstances, α =
(b) <u>Ampere's</u> <u>Law</u> to calculate magnetic field B is given by:
μ_0.
(i) First, first find for r ≤ R:
Calculating B(r), using Ampere's Law:
μ_0.
.μ_0
B(r) = .μ_0
B(r) = .μ_0
For r ≤ R, magnetic field is B(r) = .μ_0
(ii) For r ≥ R:
So, as calculated before:
I
Using Ampere:
B.2.π.r = μ_0.I
B(r) = .μ_0
For r ≥ R, magnetic field is; B(r) = .μ_0.
Answer: Gravity
Explanation: If anything thing is falling its by gravity.
Answer:
1) Measuring cylinder
2) Top Pan Balance
Explanation:
To find the density of the pebble Nabil should first accurately measure the mass of the pebble using the top pan balance
He should then fill the displacement can till the water reaches the outlet pipe at the to of the cylinder
He should then place the pebble into the cylinder carefully ans allow the water that would start coming out to stop
The volume of water in the displaced cylinder is then measured and the density is found by dividing the mass of the pebble by the volume of water in the measuring cylinder