Answer:
there's nothing here to answer

Step-by-step explanation:

Let 
Then 
or

This gives us
or all integer multiples of 
Answer:
6 1.5/4
Step-by-step explanation:
Answer:
Bouquets of roses = 20
Bouquets of carnations = 08
Step-by-step explanation:
Let,
x be the bouquets of roses sold
y be the bouquets of carnations sold
According to given statement;
x + y = 28 Eqn 1
16x + 10y = 400 Eqn 2
Multiplying Eqn 1 by 16
16(x+y=28)
16x + 16y = 448 Eqn 3
Subtracting Eqn 2 from Eqn 3
(16x+16y)-(16x+10y) = 448 - 400
16x + 16y - 16x - 10y = 48
6y = 48
Dividing both sides by 6

Putting y=8 in Eqn 1
x + 8 = 28
x = 28 - 8
x= 20
Hence,
Bouquets of roses = 20
Bouquets of carnations = 08