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7nadin3 [17]
3 years ago
8

How do you write a b c d and e in an exponent way

Mathematics
1 answer:
sesenic [268]3 years ago
6 0
Exponent way n
exponetional way
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If the integral of f(x)dx = 2.3 from 1 to 3 and F'(x) = f(x), what is the value of F(3) - F(0). The graph will be inserted as a
lana66690 [7]
<span>F(3)−F(0)=<span>∫30</span>f(x)dx</span><span>
so it looks like 2.3+1=3.3</span>
4 0
3 years ago
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4, 9, 13, 18,<br> The common difference 'd' is
Ivanshal [37]

Answer:

There is no common difference

Step-by-step explanation:

     4      9      13      18

diff     5      4       5

Because the difference between 9 and 13 is 4

and the difference in the other terms is 5

there is no common differeence

7 0
2 years ago
Help please I gotta get my grade up!​
DochEvi [55]

First step: you got to add y to both sides in the math problem Ex: 15x - y + y  < 12 + y

Second step: simplify 15x < 12 + y

Third Step: This you got to divide both sides by 15 like this: 15x/15 < 12/15 + y/15

Last and Fourth step:  Simplify and thats your answer  x < 12 + y/15

3 0
3 years ago
Asap I really need help. Is the answer 1.54??!! Please help.
mylen [45]
No. Área of a circle is determined by this formula A=πr^2. Answer is 153.94
3 0
3 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
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