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3 years ago

Simplify 15.6 divided by negative 3. . (5 points)

Mathematics

2 answers:

worty [1.4K]3 years ago

8 0

Answer: -5.2

Step-by-step explanation:

Hatshy [7]3 years ago

5 0

Answer:

5.2

Step-by-step explanation:

15.6 ÷ - 3 = - 5.2

If you divide 15.6 and negative 3 you get negative five point two.

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PLEASE HELP!

Mariana [72]

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Information Given:
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ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7

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Since it is a parallelogram:
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ON = LM and
MN = OL

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ON = LM:
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7x - 9 = 6x + 4

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Subtract 6x from both sides:
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x - 9 = 4

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Add 9 to both sides:
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x = 13

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MN = OL:
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x - 7 = 2y - 7

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Sub x = 13:
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13 - 7 = 2y - 7

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Simplify:
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6 = 2y - 7

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Add 7 on both sides:
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13 = 2y

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Divide by 2:
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y = 13/2

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Answer: x = 13, y = 13/2 (Answer D)
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6 0

3 years ago

Find all solutions to the equation. cos x = sin x

svetoff [14.1K]

If you were to draw the cosx and sinx graph there will be infinite solutions at their interceptions which are the multiple of pi/4

8 0

3 years ago

AlekseyPX

Answer:

Step-by-step explanation: just cuz

8 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

12x^6y^-4z^2/3x^2y^-6z^3

11111nata11111 [884]

Answer:

dont click the link!!

Step-by-step explanation:

5 0

3 years ago