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3 years ago

If y = kx, where k is a constant, and y = 30 when x = 6, what is the value of y when x = 3?

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

Actually it's 11 because 11 is technically the same when added to constant of x =6 = 11

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valina [46]

The answer is C I just did that question

5 0

4 years ago

Can some one help me this please

Aloiza [94]

Step by step explanation:

5X4=20
£20 for 5 hours
£20+£12=£32

Hope this helped!

4 0

3 years ago

Two sides of a triangle have the same length. The third side measures 6 m less than twice the common length. The perimeter of th

Lostsunrise [7]

Let x be the common length. Then, the sides of the triangle are x, x, and 2x-6. These three sides sum up to 22, so you have

$x+x+2x-6 = 22 \iff 4x = 28 \iff x = 7$

So, the two equal sides are 7m long, and the third side is

$2\cdot 7 - 6 = 14 - 6 = 8$

8 0

3 years ago

Use the simple interest formula (I=PxRxT and Account= P+I) to find the interest joe will earn if he deposits $2500 in an account

OLEGan [10]

Answer:

$3175

Step-by-step explanation:

Substitute the equation with the numbers.

Interest = P x R x T

Interest = 2500 x 0.045 x 6

I = 675

Add the interest amount with the original amount.

675 + 2500 = 3175

I hope this helps and please mark me as brainliest!

8 0

2 years ago

What is the distance between the lines y = 2x and y = 2x+5? Round your answer to the nearest tenth.

Ilia_Sergeevich [38]

The distance between both lines is 2.24 units

Step-by-step explanation:

There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.

Given

$y=2x\\Putting\ x=1\\y=2(1)\\y=2\\So, the\ point\ on\ y=2x\ is\ (1,2)$

We have to find the distance of this point from y=2x+5

$y=2x+5\\Subtracting\ y\ from\ both\ sides\\y-y=2x+5-y\\2x-y+5=0$

The formula for finding distance of a point (x,y) from a line is:

$d=\frac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

A=2

B=-1

C=5

Putting the values in the formula

$d=\frac{|(2)(1)+(-1)(2)+5|}{\sqrt{(2)^2+(-1)^2}}\\d=\frac{|2-2+5|}{\sqrt{4+1}}\\d=\frac{|5|}{\sqrt{5}}\\d=\frac{5}{\sqrt{5}}\\d=2.236\ units$

Rounding off will give: 2.24 units

The distance between both lines is 2.24 units

Keywords: Equations of lines

Learn more about distance in lines at:

#LearnwithBrainly

7 0

3 years ago