Answer:
Yes
Explanation:
An array is a homogeneous data structure (elements have same data type) that stores a sequence of consecutively numbered objects--allocated in contiguous memory. Each object of the array can be accessed by using its number (i.e., index). When you declare an array, you set its size.
4251.04
The perimeter (260.8) over 4 is equal to each side length (65.2)
65.2^2 = 4251.04
Answer:
The method definition to this question can be given as:
Method definition:
double max(double x, double y) //define method with double parameter
{
if (x>=y) //check condition.
return x; //return value
else
return y; //return value
}
double max(int x, int y) //define method with integer parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
double max(char x, char y) //define method with char parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
Explanation:
The above method definition can be described as below:
- In the first method definition first, we define a method that is "max()". In this method we pass two variables as a parameter that is "x and y" and the datatype of this is double. Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the second method definition, we define a method that is same as the first method name but in this method, we pass two integer variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the third method definition, we define a method that is same as the first and second method name but in this method, we pass two char variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
