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Ludmilka [50]
3 years ago
14

(Picture of question below)

Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

Second option

Step-by-step explanation:

x^(3)-4x^(2)-13x-6= (x+1) (3x + 2) (x-3)

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part 1)

so the radius of the smaller gear is 3 inches, so after a full rotation, namely a revolution, the smaller gear has covered an arc of 2π(3), or 6π.

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\bf \textit{arc's length}\\\\&#10;s=r\theta ~~&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad radians\\&#10;------\\&#10;s=6\pi \\&#10;r=7&#10;\end{cases}\implies 6\pi =7\theta \implies \cfrac{6\pi }{7}=\theta



part 2)

since the larger gear has a radius of 7, in a revolution it will have an arc of 2π(7), or 14π.

now, we know the smaller gear does a 6π arc in a revolution, how many revolutions will it do in an arc of 14π?

\bf \begin{array}{ccll}&#10;arc&revolution\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;6\pi &1\\&#10;14\pi &x&#10;\end{array}\implies \cfrac{6\pi }{14\pi }=\cfrac{1}{x}\implies \cfrac{3}{7}=\cfrac{1}{x}\implies x=\cfrac{7}{3}
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