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Mnenie [13.5K]
3 years ago
9

a triangle has two sides of length 5 and 4 what is the smallest possible whole-number length for the third side​

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

1

Step-by-step explanation:

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State a number that would lie between -2.15 and -2.16 on the number line
Aleks04 [339]

Answer:

One answer would be -2.155.

3 0
3 years ago
Read 2 more answers
What is 8 times as many as 3 is
Ainat [17]

Answer:

24?

Step-by-step explanation:

3 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

5 0
3 years ago
The perimeter of the trapezoid-shaped window frame is 23.59 feet. Write and solve an equation to find the unknown side length x
krok68 [10]

Answer:

5.62 + 3.65 + 5.62 + x = 23.59

x = 8.7 ft

Step-by-step explanation:

Perimeter of the trapezoid-shaped window = sum of all the sides of the window frame

Thus, the equation to find the unknown side length, x, would be:

✔️5.62 + 3.65 + 5.62 + x = 23.59

Solve for x

14.89 + x = 23.59

Subtract 14.89 from each side

14.89 + x - 14.89 = 23.59 - 14.89

✔️x = 8.7 ft

4 0
3 years ago
four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults
RoseWind [281]

Answer:

\pounds 26.50

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid 2x+2y that is \pounds 18, so

2x+2y=18

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid x+2x+y that is \pounds 18.50, so

x+2x+y=18.50

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid z+3x that is \pounds 19.50, so

z+3x=19.50

You get the system of three equations:

\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.

From the first equation:

2y=18-2x\\ \\y=9-x

From the third equation:

z=19.50-3x

Substitute them into the second equation:

19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5

Then

y=9-5=4\\ \\z=19.50-3\cdot 5=19.50-15=4.50

Hence,

the cost for one adult is \pounds 5

the cost for one child is \pounds 4

the cost for one senior is \pounds 4.50

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50

3 0
4 years ago
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