Add a little bit of energy and energy for your a house
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
Answer:
4/3
d/c
Step-by-step explanation:
You divide 16 by 4 and you get 4, so 4 dogs.
Then you divide 12 by 4 and you get 3, so 3 cats.
Lastly you were comparing dogs to cats so you have to put the about of days first then the amount of cats last.
The final answer is 4/3.
The answer is 49 because x = 1/7 and 1/7^-2 =49
m^2 + 12m + 35
We can factor using the sum-product, when the sum of 2 numbers is 12 and the product of those 2 numbers is 35.
7+5 = 12
7 x 5 = 35
So we have the numbers 7 and 5.
m^2 + 12m + 35 = (m+7)(m+5)
