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Oksana_A [137]
3 years ago
5

The temperature went from 48° to 36° in two hours. What is the percent of decrease in the temperature?

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0
There is a 12 degrees difference in percentage for the temperature.
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1 point) As reported in "Runner's World" magazine, the times of the finishers in the New York City 10 km run are normally distri
BigorU [14]

Answer:

(a) E (X) = 61 and SD (X) = 9

(b) E (Z) = 0 and SD (Z) = 1

Step-by-step explanation:

The time of the finishers in the New York City 10 km run are normally distributed with a mean,<em>μ</em> = 61 minutes and a standard deviation, <em>σ</em> = 9 minutes.

(a)

The random variable <em>X</em> is defined as the finishing time for the finishers.

Then the expected value of <em>X</em> is:

<em>E </em>(<em>X</em>) = 61 minutes

The variance of the random variable <em>X</em> is:

<em>V</em> (<em>X</em>) = (9 minutes)²

Then the standard deviation of the random variable <em>X</em> is:

<em>SD</em> (<em>X</em>) = 9 minutes

(b)

The random variable <em>Z</em> is the standardized form of the random variable <em>X</em>.

It is defined as:Z=\frac{X-\mu}{\sigma}

Compute the expected value of <em>Z</em> as follows:

E(Z)=E[\frac{X-\mu}{\sigma}]\\=\frac{E(X)-\mu}{\sigma}\\=\frac{61-61}{9}\\=0

The mean of <em>Z</em> is 0.

Compute the variance of <em>Z</em> as follows:

V(Z)=V[\frac{X-\mu}{\sigma}]\\=\frac{V(X)+V(\mu)}{\sigma^{2}}\\=\frac{V(X)}{\sigma^{2}}\\=\frac{9^{2}}{9^{2}}\\=1

The variance of <em>Z</em> is 1.

So the standard deviation is 1.

8 0
3 years ago
Jordan is starting to save $150 to buy a new cell phone. In December, he saved $5. In January, he plans twice as much as he did
-Dominant- [34]

Answer: At the Month May Jordan as able to get enough money to buy the phone.

Work:

December:$5

January:$10

February:$20

March:$40

April:$80

May:<em><u>$160 <--Answer</u></em>

____________________________________________________________In the problem Jordan saves $5 at December, then at January Jordan saved $10 which is twice as December's saved money amount. February, Jordan saved $20, which is twice as January's saved money amount. March is $40, which is twice as February's saved money amount. For April it is $80, which is twice as March's money amount, May is $160 which is twice as April's money amount. Or another way to say this is by starting at $5. Then, keep multiplying by 2 for each month until you get $150 or more. When you do, stop at the month that gets you $150 or more. When i did this exact method, I got $160 on the Month of May. $160 is more than enough for Jordan to buy his phone. So the month May is the correct answer where Jordan can get enough money for his phone.

3 0
3 years ago
Read 2 more answers
Can ya help me with the answer
Sergio039 [100]

23.55 feet is your answer

3 0
3 years ago
-12x2 + 45x + 12
bazaltina [42]

Answer:

3(4x + 1)(x - 4) Answer choice B

Step-by-step explanation:

-12x^2 + 45 + 12

You would take out the -3 in the equation.

-3(4x^2 -15x - 4)

You can then multiply the first 4 and the last -4 and get a -16. You can then find two numbers that would multiply to -16 and add to -15.

You would do this by listing the factors of -16, which the numbers 1 and -16 would work.

You would then substitute each value in for the 17x and add them together, which this is just separating the value 17x.

3(4x^2 - 16x + x - 4)

3(4x^2 - 16x)(x - 4)

You can then take ou ta four for the first function in the parentheses.

3(4x(x - 4) 1(x - 4))

Then you take the function from the outside and the inside.

3(4x + 1)(x - 4)

The answer to the question would be B.

8 0
3 years ago
Graph the line by locating any two ordered pairs that satisfy the equation. Round to the nearest thousandth, if necessary.
solmaris [256]

To answer the question we start by placing two ordered pairs that satisfy the equation y = 2x

To do this we enter a value of "x" and then find "y"

Let's start with x = 2

y = 2 (2)

y = 4

Then the first ordered pair that satisfies the equation is dot (2,4)

Now, for x = 0

y = 2(0)

y = 0

Then the second ordered pair that satisfies the equation is the point (0,0).

With these two pairs we draw the graph of the equation, which is shown in the attached image.

8 0
3 years ago
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