he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer:
the value has to be 54.6 and up
Step-by-step explanation:
1 - 51
2 - 129
3 - 51
5 - 90
Answer:
Multiple choice questions = 5
True questions = 15
Step-by-step explanation:
Given that:
Total number of questions = 20
Total worth of point = 100
Multiple choice questions (M) = 11 points each
True false questions (T) = 3 points each
Hence,
M + T= 20 ____(1)
11M + 3T = 100 ____(2)
M = 20 - T
Using the relation in (2)
11(20 - T) + 3T= 100
220 - 11T + 3T= 100
220 - 8T = 100
-8Tf = 100 - 220
-8T = - 120
T = 120/8
T = 15
Mc = 20 - 15
Mc = 5
Multiple choice questions = 5
True false questions = 15