Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
Answer:
slope = 5/7
Step-by-step explanation:
Given the x-intercept: (-7, 0) and the y-intecept: (0, 5):
We can use the slope formula:
Let (x1, y1) = (-7, 0)
(x2, y2) = (0, 5)
Plug these values into the slope formula:
Therefore, the slope is 5/7
1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)
A = 3.14r^2
A =3.14(144)
A = 452.16 ft²
Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²
Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²
Answer:
-2 from both sides
Step-by-step explanation:
32=5x+2
-2 -2
________
30=5x
__=__
5 5
6=x
Answer:
(4x+9)-(16x+9) = 4x+9-16x-9
= -12x