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Amanda [17]
3 years ago
13

A 3.0-ohm resistor and a 6.0-ohm resistor are

Physics
1 answer:
Alex Ar [27]3 years ago
4 0

In a series circuit, the current is the same at every point, so
the current through the 6-ohm resistor is also 4 Amperes.

 Voltage across a resistor =

                   (current through the resistor)
               times
                   (resistance of the resistor)  .

Voltage across the 6-ohm resistor =

                   (4 Amperes) x (6 ohms)  =  24 volts .

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Why does increasing loop area increase the brightness of lightbulbs
Viefleur [7K]

Answer:

Lighting Brightness: Lumens vs. Watts. Lighting technology has evolved tremendously in the past 10 years. Prior to the introduction of energy efficient light bulbs, wattage was a common measurement used to determine brightness for incandescent light bulbs.

Explanation:

4 0
3 years ago
Which factor increases as a result of increasing altitude? Air pressure, air density, heights of sea level, space between gas mo
Anuta_ua [19.1K]

Answer:

heights of sea level and the space between gas molecules.

Explanation:

Asking that Which factor increases as a result of increasing altitude?

As the height above the sea increases, air density decreases because the molecule of the air will spread out causing air density to decrease. Also, there will be less air pressing down which will lead to a decrease in air pressure.

Therefore, the heights of sea level, and space between gas molecules are the factor that will increase as a result of increasing altitude. Not Air pressure and  air density. But the heights of sea level and the space between gas molecules.

5 0
3 years ago
PLEASE HELP!!
allochka39001 [22]
The answer is c if i have not mistaken
4 0
3 years ago
Read 2 more answers
In searching the bottom of a pool at night, a watchman shines a narrow beam of light from his flashlight, 1.3 m above the water
notsponge [240]

Answer:

4.4 m

Explanation:

We are told the light from his flashlight, 1.3 m above the water level. Thus; h1 = 1.3m

Also,we are told that the light shone 2.5 m from his foot at the edge of the pool. Thus, L1 = 2.5 m

Angle of incidence θ1 is given by;

tan θ1 = L1/h1

tan θ1 = 2.5/1.3

tan θ1 = 1.9231

θ1 = tan^(-1) 1.9231

θ1 = 62.53°

Using Snell's law, we can find the angle of refraction from;

Sin θ2 = (η_air/η_water) Sin θ1

Where;

η_air is Refractive index of air = 1

η_water is Refractive index of water = 1.33

Thus;

Sin θ2 = (1/1.33) × sin 62.53°

Sin θ2 = 0.6671

θ2 = sin^(-1) 0.6671

θ2 = 41.84°

We want to find where the spot of light hit the bottom of the pool if the pool is 2.1 m deep. Thus, h2 = 2.1 m

Now, the spot can be found from;

L = L1 + L2

Where L2 = (h2) tan θ2

L = 2.5 + 2.1 tan 48.84

L = 2.5 + (2.1 × 0.8954)

L ≈ 4.4 m

7 0
3 years ago
Me pueden ayudar en esto? Por favor
kirill [66]

<span>El cubo K se llenará primero
</span>

Espera que esto ayude :)
5 0
3 years ago
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