40 meters times 1 meter over 100 centimeters equals 0.4 meters. 1.3 meters + 40 centimeters =. 1.3 m + 0.4 m = 1.7 m. The answer is 1.7 meters
Answer:
0.2289
Explanation:
Power required to climb= Fv where F is force and v is soeed. We know that F= mg hence Power, P= mgv and substituting 700 kg for m, 9.81 for g and 2.5 m/s for v then
P= 700*9.81*2.5=17167.5 W= 17.1675 kW
To express it as a fraction of 75 kw then 17.1675/75=0.2289 or 22.89%
the answer is 1a as rearrange gives I = v divided by r
Answer:
7.6 s
Explanation:
Considering kinematics formula for final velocity as
![v^{2}=u^{2}+2as](https://tex.z-dn.net/?f=v%5E%7B2%7D%3Du%5E%7B2%7D%2B2as)
Where v and u are final and initial velocities, a is acceleration and s is distance moved.
Making v the subject then
![v=\sqrt{u^{2}+2as}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bu%5E%7B2%7D%2B2as%7D)
Substituting 8.8 m/s for u, 138 m for s and 2.45 m/s2 for a then
![v=\sqrt{8.8^{2}+2*2.45*138}\\v=27.45 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B8.8%5E%7B2%7D%2B2%2A2.45%2A138%7D%5C%5Cv%3D27.45%20m%2Fs)
Also, v=u+at and making t the subject of the formula
![t=\frac {v-u}{a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%20%7Bv-u%7D%7Ba%7D)
Substituting 27.45 m/s for v, 8.8 m/s for u and 2.45 m/s for a then
![t=\frac {27.45-8.8}{2.45}=7.6122448979591\approx 7.6s](https://tex.z-dn.net/?f=t%3D%5Cfrac%20%7B27.45-8.8%7D%7B2.45%7D%3D7.6122448979591%5Capprox%207.6s)
Therefore, it needs 7.6 seconds to travel