Answer: 405.3 minutes
Explanation: In order to explain this problem we have to use the following:
Fisrtly we calculate the volume of the wire, this is given by:
Vwire=π*r^2*L where r and L are the radius and L the length of teh wire, respectively.
Vwire=π*1.25*10^-3*0.26=1.27*10^-6 m^3
then the number of the total electrons in tthe wire volume is given by;
n° electrons in the wire=ρ*Vwire=8.4*10^28*1.27*10^-6 m^3=1.07 *10^23
Finally, considering the current in the wire equal to 4.4*10^18 electrons/s
the time consuming to extract all the electrons from the wire is given by:
t= total electrons in the wire/ current=1.067*10^23/4.4*10^18=24,318 s
equivalent to 405.3 minutes
So E = 2x10^-3W/m^2*(π*(3.0x10^-3m)^2)*1min*60s... = 3.4x10^-6J
Answer:
mas of water displaced = 41.4 g
Explanation:
Weight in air = True weight = 45 g
Apparent weight = 3.6 g
Apparent weight = True weight - Buoyant force
Buoyant force = 45 g - 3.6 g = 41.4 g
Weight of water displaced = Buoyant force
Weight of water displaced = 41.4 g dyne
mas of water displaced = 41.4 g
I’ll start you off
1. Positive, negative, ions
Answer a few yourself and I’ll come back and help some more.
