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irga5000 [103]
3 years ago
11

How would it be possible for an object to be traveling with a constant speed and still accelerating?

Physics
1 answer:
lys-0071 [83]3 years ago
4 0
Yeah!! It's possible for an object by changing it's direction....
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What is a pioneer species?
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When the displacement in SHM is equal to 1/4 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Anna71 [15]

Answer:

\frac{KE}{TE} = \frac{15}{16}

b)

\frac{U}{TE} = \frac{1}{16}

Explanation:

Let the amplitude of SHM is given as A

so the total energy of SHM is given as

E = \frac{1}{2}kA^2

now we know that

a)

kinetic energy is given as

KE = \frac{1}{2}k(A^2 - x^2)

here

x = \frac{A}{4}

so now we have

KE = \frac{1}{2}k(A^2 - \frac{A^2}{16})

KE = \frac{15}{32}kA^2

now its fraction with respect to total energy is given as

\frac{KE}{TE} = \frac{15}{16}

b)

Potential energy is given as

U = \frac{1}{2}kx^2

so we have

U = \frac{1}{32}kA^2

so fraction of energy is given as

\frac{U}{TE} = \frac{1}{16}

7 0
2 years ago
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6 0
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A tennis ball is hit when it is 1.30 meters above the court. The ball's velocity leaving the racket is 8.08 m/s horizontally, ho
Greeley [361]

Answer: 4.2 m

Explanation:

The time taken by the tennis ball to cover vertical displacement 1.30 m would be the same time in which ball would cover horizontal distance.

Initial velocity of the ball, u = 8.08 m/s in horizontal direction.

Initial velocity in the vertical direction is 0.

consider upward direction as positive and downward direction as negative. The ball free falls under gravity in the vertical direction.

Using the second equation of motion,

y = u t + 0.5 at²

⇒-1.30 m = 0 + 0.5 ×(-9.8m/s²) t²

⇒t = 0.52 s

There is no external force acting in the horizontal direction, thus horizontal distance covered is:

s =  u t ⇒ s = 8.08 m/s × 0.52 s = 4.2 m

Thus, the tennis ball lands 4.2 m far away.

5 0
3 years ago
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