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irga5000 [103]
4 years ago
11

How would it be possible for an object to be traveling with a constant speed and still accelerating?

Physics
1 answer:
lys-0071 [83]4 years ago
4 0
Yeah!! It's possible for an object by changing it's direction....
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Help me with this homework please
oee [108]

Answer:

100 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 kg

Acceleration (a) = 20 m/s

Force (F) =?

Force is simply defined as the product of mass and acceleration. Mathematically, it can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the force need to move the object. This can be obtained as follow:

Mass (m) = 5 kg

Acceleration (a) = 20 m/s

Force (F) =?

F = ma

F = 5 × 20

F = 100 N

Therefore, a force of 100 N is needed to move the object.

3 0
3 years ago
How much heat is absorbed by a 125 g sample of water when it is heated from 25.20 ºc to 32.80 ºc? the specific heat of water is
Fofino [41]
We can use the equation of
E = mc△T
To calculate the total heat absorbed.
E is the total heat absorbed (energy used)
m is mass.
c is specific heat capacity and
△T is the temperature change.
E = 125 x 4.184 x (32.8 - 25.2)
E = 3974.8 J
Therofre the total heat absorbed is 3974.8 joules.
4 0
3 years ago
What is Newton third law of motion?<br>​
Harlamova29_29 [7]

Answer:

Push and pull is the 3rd motion.

7 0
4 years ago
Read 2 more answers
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting,
ad-work [718]

Answer:

EMF = 11.35 V

R = 0.031Ω

Explanation:

To find the battery's EMF and the internal resistance we need to use Ohm's law:

V = IR

Where:

V: is the voltage

I: is the current

R is the resistance

We have:

The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:

\epsilon = V + IR      

\epsilon = 9.36 V + 64.2A*R   (1)

When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:

\epsilon = 11.3 V + 1.96A*R   (2)

By solving equation (1) and (2) for R we have:

9.36 V + 64.2A*R = 11.3 V + 1.96A*R

R = \frac{1.94 V}{62.24A} = 0.031 \Omega

Hence, the internal resistance is 0.031 Ω.

Now, by entering R into equation (1) we can find the battery's EMF:

\epsilon = 9.36 V + 64.2A*0.031 \Omega

\epsilon = 11.35 V

Therefore, the battery's EMF is 11.35 V.

I hope it helps you!                

8 0
4 years ago
A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit
sertanlavr [38]
The radial force on the particle is given by the Lorentz force.  They don't give you the velocity so you have to solve for it in terms of the radius and get them to cancel.

6 0
3 years ago
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