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Nimfa-mama [501]
3 years ago
5

In a weak acid solution, _____.

Physics
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

A)

Explanation:

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A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

y = \frac{1}{2}gt^2

y = \frac{1}{2}\times 9.8 \times 10^2

y = \frac{1}{2}\times 9.8 \times 100

y = 490 m

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

speed = \frac{distance}{time}

v = \frac{650}{10}

v = 65 m/s


4 0
3 years ago
What are the conditions necessary for a terrestrial planet to have a strong magnetic field?.
Stells [14]
Both a molten metallic core and reasonably fast rotation.
6 0
2 years ago
Phase change from a liquid to a solid is what type of property change
Aliun [14]
It is to freeze an object
6 0
3 years ago
Read 2 more answers
Guys please help me ​
Likurg_2 [28]

Answer:

1)t=2.26\: s

2)S=33.9\: m

3)v=26.77\: m/s

4)\alpha=55.92

Explanation:

1)

We can use the following equation:

y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

0=25-0.5*9.81*t^{2}

t=2.26\: s

2)

The equation of the motion in the x-direction is:

v_{ix}=\frac{S}{t}

15=\frac{S}{2.26}

S=33.9\: m

3)

The velocity in the y-direction of the stone will be:

v_{fy}=v_{iy}-gt

v_{fy}=0-(9.81*2.26)

v_{fy}=-22.17\: m/s

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}

v=26.77\: m/s

4)

The angle of this velocity is:

tan(\alpha)=\frac{22.17}{15}

\alpha=tan^{-1}(\frac{22.17}{15})

\alpha=55.92

Then α=55.92° negative from the x-direction.

I hope it helps you!

6 0
3 years ago
A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, mov
lions [1.4K]

Answer:

the total momentum is 8 .2 kg m/s in north direction.

Explanation:

given,

mass(m₁) 3.00 kg, moving north at v₁ = 3.00 m/s

mass(m₂) 4.00 kg, moving south at v₂ =  3.70 m/s

mass(m₃) 7.00 kg, moving north at v₃ = 2.00 m/s

north as the positive axis

south as the negative axis

now

total momentum = m₁v₁ + m₂ v₂ + m₃ v₃

total momentum = 3 x 3 - 4 x 3.7 + 7 x 2

                           = 9 - 14.8 + 14

                           = 8 .2 kg m/s

hence, the total momentum is 8 .2 kg m/s in north direction.

7 0
3 years ago
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