Answer:
D
Explanation:
correct me if I'm wrong on your answer and it's the right answer from my son
Answer:
The speed of the wind is 25 km/hr.
Explanation:
Let us call
the speed of the plane and
the speed of the wind. When the plane is flying against the wind, it covers the distance of 900-km in 2 hours (120 minutes); therefore;
(1). ![v_p - v_w = \dfrac{900km}{120min}](https://tex.z-dn.net/?f=v_p%20-%20v_w%20%3D%20%5Cdfrac%7B900km%7D%7B120min%7D)
And when the plane is flying with the wind, it covers the same distance in 1 hour 48 minutes (108 minutes)
(2). ![v_p+v_w= \dfrac{900km}{108min}](https://tex.z-dn.net/?f=v_p%2Bv_w%3D%20%5Cdfrac%7B900km%7D%7B108min%7D)
From equation (1) we solve for
and get:
,
and by putting this into equation (2) we get:
![\dfrac{900km}{120min}+v_w+v_w= \dfrac{900km}{108min}](https://tex.z-dn.net/?f=%5Cdfrac%7B900km%7D%7B120min%7D%2Bv_w%2Bv_w%3D%20%5Cdfrac%7B900km%7D%7B108min%7D)
![2v_w= \dfrac{900km}{108min}-\dfrac{900km}{120min}](https://tex.z-dn.net/?f=2v_w%3D%20%5Cdfrac%7B900km%7D%7B108min%7D-%5Cdfrac%7B900km%7D%7B120min%7D)
![2v_w = 8.3km/min - 7.5km/min](https://tex.z-dn.net/?f=2v_w%20%3D%208.3km%2Fmin%20-%207.5km%2Fmin)
![2v_w = 0.83km/min](https://tex.z-dn.net/?f=2v_w%20%3D%200.83km%2Fmin)
![v_w = 0.4165km/min](https://tex.z-dn.net/?f=v_w%20%3D%200.4165km%2Fmin)
or in km/hr this is
![\boxed{v_w= 25km/hr }](https://tex.z-dn.net/?f=%5Cboxed%7Bv_w%3D%2025km%2Fhr%20%7D)
The answer to your question is capacitor :)
Answer:
A transformed, visible pattern on earth that holds cues indicating the presence of a particular ethnic group is cultural landscape.
Explanation:
<u>Answer:</u>
2N/cm
<u>Step-by-step explanation:</u>
According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:
![F=kx](https://tex.z-dn.net/?f=F%3Dkx)
where,
is the force which is stretching or compressing the spring,
is the spring constant; and
is the distance the spring is stretched.
Substituting the given values to find the elastic constant
to get:
![F=kx](https://tex.z-dn.net/?f=F%3Dkx)
![4=k(2)](https://tex.z-dn.net/?f=4%3Dk%282%29)
![k=\frac{4}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B4%7D%7B2%7D)
![k=2](https://tex.z-dn.net/?f=k%3D2)
Therefore, the elastic constant is 2 Newton/cm.