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uranmaximum [27]
3 years ago
12

H(x)=x-12/4 inverse function with steps please​

Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer: x = H(x) + 3

Step-by-step explanation: The inverse function is x expressed with H(x). There aren't always inverse functions but in this case you just put the fraction from the right hand side to the left hand side. After the divison you get what I wrote.

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Using Parallel Lines Find m 1 and m 2. Explain your reasoning.
Molodets [167]

i don't know if there is a graph for this problem, but m1 should always equal m2

if m1 and m2 are parallel, one line that is perpendicular to m1 is always perpendicular to m2, and the slopes of m1 and m2 are equal and their lines should never intersect

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3 years ago
Rosario is rolling a six-sided number cube. Rosario rolls the number cube twice. What is the probability that Rosario gets the n
Marat540 [252]
It's a conditional probability

P( getting a given number AND getting again the same number)


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7 0
3 years ago
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Find the volume of the figure below.
PSYCHO15rus [73]
The triangle area is 7*2/2 = 7.
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Answer A!
7 0
3 years ago
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Please help me find the answer ASAP. Thanks
jenyasd209 [6]
This is very easy question write all given and common
3 0
3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
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