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klemol [59]
3 years ago
8

LCM of 15 and 50? Please explain.

Mathematics
1 answer:
levacccp [35]3 years ago
8 0
The LCM of 15 and 50 is 150
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Write a function rule for the area of rectangle whose length is 2ft more than its width. What is the area of the rectangle when
Marianna [84]

According to the problem, the length is 2 feet more than its width, which is expressed as the following function

l=w+2

If the width is x, then the length is x+2.

We can express the following function for the area

A(x)=x(x+2)

Let's replace the width x = 11 ft.

A(11)=11\cdot(11+2)=11(13)=143<h2>Hence, the area is 143 square feet. </h2><h2>The function for the area is</h2>A(x)=x(x+2)

Where x represents the width.

3 0
1 year ago
The diagram below shows a large square with two smaller squares within it.
deff fn [24]

Answer:

The shaded area is 23\ in^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

so

A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})

A=(2^{2})(3^{2}) -(3^{2} +2^{2}) ---> expression that represent the shaded area

Calculate the shaded area

Remember that

3^{2}=9\\ 2^{2}=4

substitute

A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}

7 0
4 years ago
Round 8.41315 correct to 2 decimal places
Nadya [2.5K]

Answer:

8.41

Step-by-step explanation:

i think

5 0
3 years ago
What is the answer for this too?
Vikki [24]
The answers once compounded equals $65068.44. Hope this helps:)
8 0
4 years ago
Consider the figure.<br> Find AB if BC = 3, BD = 5, and AD = 5.<br><br> AB= ?
blondinia [14]
Answer is 9.5 First find DC by doing the Pythagorean theorem
BC is 3 BD is 5
So 3^2+ DC= 5^2
9+____=25
So DC is 4 cuz 4times 4=16

Now add AD+DC=AC

5+4=9

So BC is 3 the bottom AC is 9
3^2+9^2= 9+81=90 the sq rt of 90 is 9.5
7 0
4 years ago
Read 2 more answers
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